时间:2021-07-01 10:21:17 帮助过:67人阅读
表结构:
数据:
需求:
按照company_id不同分组,然后分别求出相同company_id相邻记录touch_time的差值
SQL:
select r1.company_id, r1.touch_time, r2.touch_time, r1.touch_time - r2.touch_time from (select (@rownum := @rownum + 1) as rownum, info.company_id, info.touch_time from sys_touch_info info, (select @rownum := 0) r where info.touch_time is not null order by info.company_id) r1 left join (select (@index := @index + 1) as rownum, info.company_id, info.touch_time from sys_touch_info info, (select @index := 0) r where info.touch_time is not null order by info.company_id) r2 on r1.company_id = r2.company_id and r1.rownum = r2.rownum - 1
结果:
以上这篇Mysql 相邻两行记录某列的差值方法就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持脚本之家。