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如何通过SQL找出2个表里值不同的列的方法

时间:2021-07-01 10:21:17 帮助过:27人阅读

以下有两个表,他们的结构完全相同,请通过SQL找出值不同的列。

Student_1

NAME AGE SCORE
peter 26 100
jack 25 96
daniel 26 48
bark 21 69

 

 

Student_2

NAME AGE SCORE
peter 26 89
jack 25 96
daniel 26 48
bark 21 69

 

方法一 -- NOT EXISTS:

代码如下:

SELECT *
FROM Student_1 S1
WHERE NOT EXISTS
  (SELECT *
  FROM Student_2 S2
  WHERE S1.name = S2.name
  AND S1.age    = S2.age
  AND S1.score  = S2.score
  )
UNION ALL
SELECT *
FROM STUDENT_2 S2
WHERE NOT EXISTS
  (SELECT *
  FROM STUDENT_1 S1
  WHERE S1.name = S2.name
  AND S1.age    = S2.age
  AND S1.score  = S2.score
  );

方法二 -- MINUS

代码如下:

(SELECT * FROM Student_1
MINUS
SELECT * FROM Student_2)
UNION ALL
(SELECT * FROM Student_2
MINUS
SELECT * FROM Student_1)

方法三 -- HAVING GROUP BY

代码如下:

SELECT DISTINCT name, age, score FROM (
SELECT * FROM Student_1
UNION ALL
SELECT * FROM Student_2
)GROUP BY name, age, score HAVING COUNT(*)=1 ;

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