当前位置:Gxlcms > html代码 > 如何点击a标签实现弹出inputfile上传文件对话框

如何点击a标签实现弹出inputfile上传文件对话框

时间:2021-07-01 10:21:17 帮助过:53人阅读

html

代码如下:

<SPAN class=tag><<SPAN class=title>div</SPAN>></SPAN>
<SPAN class=tag><<SPAN class=title>a</SPAN> <SPAN class=attribute>href</SPAN>=<SPAN class=value>"###"</SPAN>></SPAN>添加图片<SPAN class=tag></<SPAN class=title>a</SPAN>></SPAN>
<SPAN class=tag><<SPAN class=title>input</SPAN> <SPAN class=attribute>type</SPAN>=<SPAN class=value>"file"</SPAN> <SPAN class=attribute>name</SPAN>=<SPAN class=value>"image"</SPAN> <SPAN class=attribute>class</SPAN>=<SPAN class=value>"hidden"</SPAN> <SPAN class=attribute>value</SPAN>=<SPAN class=value>""</SPAN> /></SPAN>
<SPAN class=tag></<SPAN class=title>div</SPAN>></SPAN>

css

代码如下:

<SPAN class=class>.hidden</SPAN> <SPAN class=rules>{
<SPAN class=rule><SPAN class=attribute>display</SPAN>:<SPAN class=value> none;</SPAN></SPAN>
<SPAN class=rule>}</SPAN></SPAN>


代码如下:

jquery
$('a').on('click', function(e) {
e.preventDefault();
$(this).closest('input[type=file]').trigger('click');
})

人气教程排行