时间：2021-07-01 10:21:17 帮助过：28人阅读
AJAX拖拽上传功能实现，供大家参考，具体内容如下
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta http-equiv="X-UA-Compatible" content="ie=edge">
<title>Document</title>
<style>
.box {
width: 300px;
height: 300px;
border: 1px solid #000;
text-align: center;
line-height: 300px;
font-size: 40px;
}
</style>
</head>
<body>
<div class="box">+</div>
<script>
var box = document.querySelector('.box');
box.ondragover = function (e) {
e.preventDefault();
}
box.ondrop = function (e) {
console.log(e.dataTransfer)
e.preventDefault();
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function () {
if (xhr.readyState == 4 && xhr.status == 200) {
console.log(xhr.responseText)
}
}
xhr.open('POST', './server.php', true);
var formdata = new FormData();
formdata.append('pic', e.dataTransfer.files[0]);
formdata.append('name', 'luyao');
xhr.send(formdata);
}
</script>
</body>
</html>
//server.php
<?php $rand = rand(1,1000).'.jpg'; move_uploaded_file($_FILES['pic']['tmp_name'], './uploads/'.$rand); echo '/uploads/'.$rand;
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持脚本之家。