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Laravel点击页面链接按某一条件排序,这个页面的更新链接应该如何写?

时间:2021-07-01 10:21:17 帮助过:39人阅读

如题。。一个图片的展示页面,如果我想根据某一条件排序,例如根据ID倒序排序,那么这个在blade.php的条件更新链接应该怎样写

public function index()
    {
        $images = Image::paginate(10);
        return view('images-list',compact('images'));
    }
//想根据ID倒序,(请问这样的情况需要另外新开一个controller吗)
public function idsort()
    {
        $images = Image::paginate(10);
        $idsort = $images->sortByDesc('id');
        return view('test',compact('images','idsort'));
    }

@forelse($images as $image)
         
            
               
               
                  
{{$image->caption}}

{!! substr($image->description, 0,100) !!}

id.'/edit') }}" class="btn btn-warning pull-left">Edit {!! Form::open(['url'=>'/image/'.$image->id, 'class'=>'pull-left']) !!} {!! Form::hidden('_method', 'DELETE') !!} {!! Form::submit('Delete', ['class' => 'btn btn-danger', 'onclick'=>'return confirm(\'Are you sure?\')']) !!} {!! Form::close() !!}

@empty

No images yet, add a new one?

@endforelse

回复内容:

如题。。一个图片的展示页面,如果我想根据某一条件排序,例如根据ID倒序排序,那么这个在blade.php的条件更新链接应该怎样写

public function index()
    {
        $images = Image::paginate(10);
        return view('images-list',compact('images'));
    }
//想根据ID倒序,(请问这样的情况需要另外新开一个controller吗)
public function idsort()
    {
        $images = Image::paginate(10);
        $idsort = $images->sortByDesc('id');
        return view('test',compact('images','idsort'));
    }

@forelse($images as $image)
         
            
               
               
                  
{{$image->caption}}

{!! substr($image->description, 0,100) !!}

id.'/edit') }}" class="btn btn-warning pull-left">Edit {!! Form::open(['url'=>'/image/'.$image->id, 'class'=>'pull-left']) !!} {!! Form::hidden('_method', 'DELETE') !!} {!! Form::submit('Delete', ['class' => 'btn btn-danger', 'onclick'=>'return confirm(\'Are you sure?\')']) !!} {!! Form::close() !!}

@empty

No images yet, add a new one?

@endforelse

已经看到这个问题多次了,这不叫更新,你只需要对查询时排序即可。

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