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php&java(二)

时间:2021-07-01 10:21:17 帮助过:4人阅读

例子1:创建和使用你自己的JAVA类
创建你自己的JAVA类非常容易。新建一个phptest.java文件,将它放置在你的java.class.path目录下,文件内容如下:

public class phptest{
/**
* A sample of a class that can work with PHP
* NB: The whole class must be public to work, 
* and of course the methods you wish to call
* directly.
*
* Also note that from PHP the main method
* will not be called 
*/

public String foo;

/**
* Takes a string and returns the result
* or a msg saying your string was empty
*/
public String test(String str) {  
if(str.equals("")) {
   str = "Your string was empty. ";  
}  
return str; 
}

/**
* whatisfoo() simply returns the value of the variable foo.
*/ 
public String whatisfoo() {  
return "foo is " + foo; 
}


/**
* This is called if phptest is run from the command line with
* something like
* java phptest
* or
* java phptest hello there
*/
public static void main(String args[]) {
phptest p = new phptest();
  
if(args.length == 0) {
String arg = "";
System.out.println(p.test(arg));
}else{
for (int i=0; i < args.length; i++) {
String arg = args[i];
System.out.println(p.test(arg)); 
}
}
}
}

创建这个文件后,我们要编译好这个文件,在DOS命令行使用javac phptest.java这个命令。

为了使用PHP测试这个JAVA类,我们创建一个phptest.php文件,内容如下:


$myj = new Java("phptest");
echo "Test Results are " . $myj->test("Hello World") . "";
 
$myj->foo = "A String Value";
echo "You have set foo to "  . $myj->foo . "
n";
echo "My java method reports: " . $myj->whatisfoo() . "
n";
 
?>

如果你得到这样的警告信息:java.lang.ClassNotFoundException error ,这就意味着你的phptest.class文件不在你的java.class.path目录下。
注意的是JAVA是一种强制类型语言,而PHP不是,这样我们在将它们融合时,容易导致错误,于是我们在向JAVA传递变量时,要正确指定好变量的类型。如:$myj->foo = (string) 12345678; or $myj->foo = "12345678";

这只是一个很小的例子,你可以创建你自己的JAVA类,并使用PHP很好的调用它!

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