简单示例AJAX结合PHP代码实现登录效果代码_PHP
时间：2021-07-01 10:21:17
帮助过：6人阅读
Ajax
HTML部分：
function postRequest(strURL){
var xmlHttp;
if(window.XMLHttpRequest){ // For Mozilla, Safari, ...
var xmlHttp = new XMLHttpRequest();
}
else if(window.ActiveXObject){ // For Internet Explorer
var xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlHttp.open('POST', strURL, true);
xmlHttp.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');
xmlHttp.onreadystatechange = function(){
if (xmlHttp.readyState == 4){
updatepage(xmlHttp.responseText);
}
}
xmlHttp.send(strURL);
}
function updatepage(str){
if(str=="yes"){
alert("Welcome User");
}else{
alert("Invalid Login! Please try again!");
}
}
function call_login(){
var username = window.document.f1.username.value;
var password = window.document.f1.password.value;
var url = "login.php?username=" + username + "&password=" +password ;
postRequest(url);
}
PHP脚本部分login.php：
$username=$_GET["username"];
$password=$_GET["password"];
if($username=="admin" && $password=="admin"){
echo "yes";
}else{
echo "No";
}
?>
