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PHP获取一年有几周以及每周开始日期和结束日期_PHP

时间:2021-07-01 10:21:17 帮助过:16人阅读

最近接了一个项目,其中有一需求是用php获取一年有几周以及每周开始日期和接触日期。在网上找些资料没有合适的,于是自己做了一份,下面通过两种方式实现PHP获取一年有几周以及每周开始日期和结束日期

代码一:

<?php
header("Content-type:text/html;charset=utf-8");
date_default_timezone_set("Asia/Shanghai");
$year = (int)$_GET['year'];
$week = (int)$_GET['week'];
$weeks = date("W", mktime(0, 0, 0, 12, 28, $year));
echo $year . '年一共有' . $weeks . '周
'; if ($week > $weeks || $week <= 0) { $week = 1; } if ($week < 10) { $week = '0' . $week; } $timestamp['start'] = strtotime($year . 'W' . $week); $timestamp['end'] = strtotime('+1 week -1 day', $timestamp['start']); echo $year . '年第' . $week . '周开始时间戳:' . $timestamp['start'] . '
'; echo $year . '年第' . $week . '周结束时间戳:' . $timestamp['end'] . '
'; echo $year . '年第' . $week . '周开始日期:' . date("Y-m-d", $timestamp['start']) . '
'; echo $year . '年第' . $week . '周结束日期:' . date("Y-m-d", $timestamp['end']); ?>

代码二:

<?php
header("Content-type:text/html;charset=utf-8");
function getIsoWeeksInYear($year)
{
 $date = new DateTime;
 $date->setISODate($year, 53);
 return ($date->format("W") === "53" ? 53 : 52);
}
function weekday($custom_date)
{
 $week_start = date('d-m-Y', strtotime('this week monday', $custom_date));
 $week_end = date('d-m-Y', strtotime('this week sunday', $custom_date));
 $week_array[0] = $week_start;
 $week_array[1] = $week_end;
 return $week_array;
}
echo '
Weeks in 2013
' . getIsoWeeksInYear(2013); $weekday = weekday(strtotime(date('d-m-Y', strtotime('5-8-2013')))); echo '
10-8-2013'; echo '
Start: ' . $weekday[0]; echo '
End: ' . $weekday[1]; ?>

以上本文的全部内容,希望对大家学习PHP获取一年有几周以及每周开始日期和结束日期,有所帮助。

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