时间:2021-07-01 10:21:17 帮助过:19人阅读
// file to read $file = 'test.jpg'; $image = exif_thumbnail($file, $width, $height, $type); // width, height and type get filled with data // after calling "exif_thumbnail" if ($image) { // send header and image data to the browser: header('Content-type: ' .image_type_to_mime_type($type)); print $image; } else { // there is no thumbnail available, handle the error: print 'No thumbnail available'; }
希望本文所述对大家的php程序设计有所帮助。