时间:2021-07-01 10:21:17 帮助过:2人阅读
<?php header('meta http-equiv="content-type"content="text/html; charset=gb2312"'); if( isset( $_REQUEST['submit']) && isset( $_REQUEST['key'])) $key = $_REQUEST['key']; else $key = '周杰伦'; $url = 'http://music.sina.com.cn/yueku/search/getRecommendXml1dot0.php?q='.urlencode($key).'&l=50&json=json'; $data = file_get_contents( $url); $data = json_decode( $data); if( !count($data)) echo 'Not found'; ?><?php foreach( $data as $one){ $music = $one->MP3URL; $music = file_get_contents( $music); $music = str_replace('iask_music_song_url="' , '', str_replace('";' , '', $music)); ?> <?php echo 'ALBUM_NAME : '.$one->NAME.' MUSIC_URL : '.$one->NAME.''.' SINGER_NAME'.$one->SINGERCNAME;?> <?php } ?>
希望本文所述对大家的php程序设计有所帮助。