php桌面中心(三)修改数据库_php实例

下面这个程序在你输入id后就把那个id的数据列出来。然后你就可以修改后写入了.

数据库的数据更新

if(isset($id))
{
if(!mysql_connect("localhost","用户名","密码"))
{echo"无法联接数据库";
exit();
}
if(isset($url))
{
$query="update $jpg set id='$id',url='$url',mess='$mess',
fromx='$fromx',url1='$url1',mess1='$mess1',fromx1='$fromx1',url2='$url2',
mess2='$mess2',fromx2='$fromx2',url3='$url3',mess3='$mess3',fromx3='$fromx3'
where id='$id'" ;
$result=mysql_db_query("elong",$query); //执行写入
if (!$result)
{echo "发生错误!";
exit();
}
echo "$id 已经更新!

";
echo "n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n
n

ID	$id
url地址	$url
小图	$mess
说明	$fromx
url地址1	$url1
小图1	$mess1
说明1	$fromx1
url地址2	$url2
小图2	$mess2
说明2	$fromx2
url地址3	$url3
小图3	$mess3
说明3	$fromx3

n";
echo "回到首页";
exit();
}
$query="SELECT id,url,mess,fromx,url1,mess1,fromx1,url2,mess2,fromx2,url3,mess3,fromx3 from $jpg
where id='$id'" ;
$result=mysql_db_query("elong",$query);
if (!$result)
{echo "发生错误!";
exit();
}
$r=mysql_fetch_array($result);
$id = $r["id"];
$url = $r["url"];
$mess = $r["mess"];
$fromx = $r["fromx"];
$url1 = $r["url1"];
$mess1 = $r["mess1"];
$fromx1 = $r["fromx1"];
$url2 = $r["url2"];
$mess2 = $r["mess2"];
$fromx2 = $r["fromx2"];
$url3 = $r["url3"];
$mess3 = $r["mess3"];
$fromx3 = $r["fromx3"];
echo"
n";
}
else
{?>

请输放需要更改的id: