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php判断正常访问和外部访问的示例_php技巧

时间:2021-07-01 10:21:17 帮助过:16人阅读

php判断正常访问和外部访问
代码如下:
  1. <br><!--?php <BR-->session_start(); <br>if(isset($_POST['check'])&&!empty($_POST['name'])){ <br>if($_POST['check'] == $_SESSION['check']){ <br>echo "正常访问"; <br>}else{ <br>echo "外部访问"; <br>} <br>} <br>$token = md5(uniqid(rand(),true)); <br>$_SESSION['check'] = $token; <br>?> <br><form method="post" action=""> <br><input type="text" name="name"> <br><input type="text" name="check" value="<?=$token;?>"> <br><input type="submit"> <br> </form>

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