时间:2021-07-01 10:21:17 帮助过:6人阅读
下面这段php代码可不透露实际的文件下载地址。
function download_document($filename,$path="",$mimetype="application/octet-stream") { header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Disposition: attachment; filename = $filename"); header("Content-Length: " . filesize($pathto . $filename)); header("Content-Type: $mimetype"); echo file_get_contents($pathto . $filename); }
实现方法二:
<?php $file = "1.txt";// 文件的真实地址(支持url,不过不建议用url) if (file_exists($file)) { header('Content-Description: File Transfer'); header('Content-Type: application/octet-stream'); header('Content-Disposition: attachment; filename='.basename($file)); header('Content-Transfer-Encoding: binary'); header('Expires: 0'); header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); header('Pragma: public'); header('Content-Length: ' . filesize($file)); ob_clean(); flush(); readfile($file); exit; } ?>
希望本文所述对大家的php程序设计有所帮助。