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深入extjs与php参数交互的详解

时间:2021-07-01 10:21:17 帮助过:26人阅读

代码如下:
<html>
 <head>
  <title>HelloWorld</title>
  <meta http-equiv="Content-Type" content="text/html; charset=utf-8">
  <link rel="stylesheet" type="text/css" href="../../ext-4.0.7-gpl/resources/css/ext-all.css" >
  <script type="text/javascript" src="../../ext-4.0.7-gpl/bootstrap.js"></script>
  <script type="text/javascript" src="../../ext-4.0.7-gpl/locale/ext-lang-zh_CN.js"></script>
  <script type="text/javascript">
   Ext.onReady(function(){
    var requestConfig = {
     url:'loginServer.php', //请求的服务器地址
     params:{userName:'lowkey', password:'zq19890319'}, //请求参数
     method : "post",
     callback:function(options, success, response) {
         var msg=["请求是否成功:", success, "\n",
           "服务器返回值:", response.responseText];
         Ext.Msg.alert("提示", response.responseText);
        }
    }
    Ext.Ajax.request(requestConfig);
   });

  </script>
 </head>

 <body>
 </body>
</html>

代码如下:
<?php
 $userName = $_POST["userName"];
 $password = $_POST["password"];
 $msg = "";
 if($userName=="lowkey" && $password=="zq19890319") {
  $msg = "登陆成功";
 } else {
 $msg = "登陆失败";
 }
 echo($msg);
?>

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