时间:2021-07-01 10:21:17 帮助过:30人阅读
本文实例为大家分享了基于PHP+jQuery+MySql实现红蓝(顶踩)投票代码,供大家参考,具体内容如下
数据库操作:
CREATE TABLE IF NOT EXISTS `votes` ( `id` int(10) NOT NULL AUTO_INCREMENT, `likes` int(10) NOT NULL DEFAULT '0', `unlikes` int(10) NOT NULL DEFAULT '0', PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; INSERT INTO `votes` (`id`, `likes`, `unlikes`) VALUES (1, 30, 10); CREATE TABLE IF NOT EXISTS `votes_ip` ( `id` int(10) NOT NULL, `vid` int(10) NOT NULL, `ip` varchar(40) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=utf8;
div:
<div class="digg"> <div id="dig_up" class="digup"> <span id="num_up"></span> <p>很好,很强大!</p> <div id="bar_up" class="bar"><span></span><i></i></div> </div> <div id="dig_down" class="digdown"> <span id="num_down"></span> <p>太差劲了!</p> <div id="bar_down" class="bar"><span></span><i></i></div> </div> <div id="msg"></div> </div>
css:
.digg{width:420px; height:120px; margin:80px auto 20px auto; position:relative} #dig_up,#dig_down{width:200px; height:48px; margin:10px; position:relative; border:1px solid #d3d3d3; padding-left:42px; cursor:pointer} .digup{background:url(diggs.png) no-repeat 4px 2px;} .digup_on{background:url(diggs.png) no-repeat 4px -49px;} .digdown{background:url(diggs.png) no-repeat 4px -102px;} .digdown_on{background:url(diggs.png) no-repeat 4px -154px;} #num_up,#num_down{position:absolute; right:6px; top:18px; font-size:20px;} #dig_up p{height:24px; line-height:24px; color:#360} #dig_down p{height:24px; line-height:24px; color:#f30} .bar{width:100px; height:12px; line-height:12px; border:1px solid #f0f0f0; position:relative; text-align:center} .bar span{display:block; height:12px; } .bar i{position:absolute; top:0; left:104px;} #bar_up span{background:#360} #bar_down span{background:#f60} #msg{position:absolute; right:20px; top:40px; font-size:18px; color:#f00}
jquery:
$(function(){ //鼠标滑向和离开投票按钮时,变换背景样式 $("#dig_up").hover(function(){ $(this).addClass("digup_on"); },function(){ $(this).removeClass("digup_on"); }); $("#dig_down").hover(function(){ $(this).addClass("digdown_on"); },function(){ $(this).removeClass("digdown_on"); }); //初始化数据 getdata("do.php",1); //单击“顶”时 $("#dig_up").click(function(){ getdata("do.php?action=like",1); }); //单击“踩”时 $("#dig_down").click(function(){ getdata("do.php?action=unlike",1); }); }); --------------------------------------- function getdata(url,sid){ $.getJSON(url,{id:sid},function(data){ if(data.success==1){//投票成功 $("#num_up").html(data.like); //通过控制宽度来显示百分比进度条效果 $("#bar_up span").css("width",data.like_percent); $("#bar_up i").html(data.like_percent); $("#num_down").html(data.unlike); $("#bar_down span").css("width",data.unlike_percent); $("#bar_down i").html(data.unlike_percent); }else{//投票失败 $("#msg").html(data.msg).show().css({'opacity':1,'top':'40px'}) .animate({top:'-50px',opacity:0}, "slow"); } }); }
php:
include_once("connect.php");//连接数据库 $action = $_GET['action']; $id = 1; $ip = get_client_ip();//获取ip if($action=='like'){//顶 likes(1,$id,$ip); }elseif($action=='unlike'){//踩 likes(0,$id,$ip); }else{ echo jsons($id); } ------------------------------------ function likes($type,$id,$ip){ $ip_sql=mysql_query("select ip from votes_ip where vid='$id' and ip='$ip'"); $count=mysql_num_rows($ip_sql); if($count==0){//还没有顶过 if($type==1){//顶 $sql = "update votes set likes=likes+1 where id=".$id; }else{//踩 $sql = "update votes set unlikes=unlikes+1 where id=".$id; } mysql_query($sql); $sql_in = "insert into votes_ip (vid,ip) values ('$id','$ip')"; mysql_query($sql_in); if(mysql_insert_id()>0){ echo jsons($id); }else{ $arr['success'] = 0; $arr['msg'] = '操作失败,请重试'; echo json_encode($arr); } }else{ $msg = $type==1?'您已经顶过了':'您已经踩过了'; $arr['success'] = 0; $arr['msg'] = $msg; echo json_encode($arr); } } -----------php------------------------- function jsons($id){ $query = mysql_query("select * from votes where id=".$id); $row = mysql_fetch_array($query); $like = $row['likes']; $unlike = $row['unlikes']; $arr['success']=1; $arr['like'] = $like; $arr['unlike'] = $unlike; $like_percent = round($like/($like+$unlike),3)*100; $arr['like_percent'] = $like_percent.'%'; $arr['unlike_percent'] = (100-$like_percent).'%'; return json_encode($arr); }
以上就是本文的全部内容,希望对大家学习php程序设计有所帮助。