时间:2021-07-01 10:21:17 帮助过:17人阅读
本文实例讲述了php根据日期显示所在星座的方法,具体实现方法如下:
- <?php
- function zodiac($DOB){
- $DOB = date("m-d", strtotime($DOB));
- list($month,$day) = explode("-",$DOB);
- if(($month == 3 || $month == 4) && ($day > 22 || $day < 21)){
- $zodiac = "Aries";
- }
- elseif(($month == 4 || $month == 5) && ($day > 22 || $day < 22)){
- $zodiac = "Taurus";
- }
- elseif(($month == 5 || $month == 6) && ($day > 23 || $day < 22)){
- $zodiac = "Gemini";
- }
- elseif(($month == 6 || $month == 7) && ($day > 23 || $day < 23)){
- $zodiac = "Cancer";
- }
- elseif(($month == 7 || $month == 8) && ($day > 24 || $day < 22)){
- $zodiac = "Leo";
- }
- elseif(($month == 8 || $month == 9) && ($day > 23 || $day < 24)){
- $zodiac = "Virgo";
- }
- elseif(($month == 9 || $month == 10) && ($day > 25 || $day < 24)){
- $zodiac = "Libra";
- }
- elseif(($month == 10 || $month == 11) && ($day > 25 || $day < 23)){
- $zodiac = "Scorpio";
- }
- elseif(($month == 11 || $month == 12) && ($day > 24 || $day < 23)){
- $zodiac = "Sagittarius";
- }
- elseif(($month == 12 || $month == 1) && ($day > 24 || $day < 21)){
- $zodiac = "Cpricorn";
- }
- elseif(($month == 1 || $month == 2) && ($day > 22 || $day < 20)){
- $zodiac = "Aquarius";
- }
- elseif(($month == 2 || $month == 3) && ($day > 21 || $day < 21)){
- $zodiac = "Pisces";
- }
- return $zodiac;
- }
- echo zodiac('1986-07-22'); //Valid strtotime date
- ?>
总结:以上就是本篇文的全部内容,希望能对大家的学习有所帮助。
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