php一次性大量数据入库如何解决

数据库的update 如果使用case when 的话,也是可以批量更新的,本人在百度上找到了一个基于tp的saveAll()方法,用于更新数据

本文主要讲关于批量insert;

例:

生成一个订单

正常情况的语句为:

INSERT INTO order (`goods_id`,`num`,`price`) VALUES (1,1,'10.00');
//封装成函数
function add_order($goods_id,$num,$price){
$db->query("INSERT INTO order (`goods_id`,`num`,`price`) VALUES ($goods_id,$num,$price)");
}

假设有一个用户,一次性将购物车的1000个商品结算成订单,生成1000个订单时;

for ($i=0;$i<1000;$i++){
$db->query("INSERT INTO order (`goods_id`,`num`,`price`) VALUES ($goods_id,$num,$price)");
}
//这样的话会导致服务器资源占用过大,网站卡死
//所以,我们可以
$sql = "INSERT INTO order (`goods_id`,`num`,`price`) VALUES ";
for ($i=0;$i<1000;$i++){
    if($i==0){
    $sql.="($goods_id,$num,$price)";
    }else{
    $sql.=",($goods_id,$num,$price)";
    }
}
$db->query($sql);

大概意思就是这样了,批量更新实现比较麻烦一点,就不发了,以下是批量更新的sql执行语句

UPDATE tiyan.dm_user_cupboard SET `res_id` = CASE `id` WHEN 1041 THEN '1' WHEN 1058 THEN '1' WHEN 1055 THEN '1' END,`food_code` = CASE `id` WHEN 1041 THEN '68' WHEN 1058 THEN '47' WHEN 1055 THEN '49' END,`food_name` = CASE `id` WHEN 1041 THEN '红枣' WHEN 1058 THEN '莲藕' WHEN 1055 THEN '洋葱' END,`num` = CASE `id` WHEN 1041 THEN '2' WHEN 1058 THEN '3' WHEN 1055 THEN '2' END,`level` = CASE `id` WHEN 1041 THEN '2' WHEN 1058 THEN '2' WHEN 1055 THEN '2' END,`update_time` = CASE `id` WHEN 1041 THEN '2017-12-09 21:40:06' WHEN 1058 THEN '2017-12-09 21:40:06' WHEN 1055 THEN '2017-12-09 21:40:06' END WHERE id IN ( 1041,1058,1055 )

附带基于tp的saveAll()

//批量更新
public function saveAll($datas,$model){
    ( $model || $model=$this->tableName);
    $model=empty($model)?$this->name:$model;
    $sql   = ''; //Sql
    $lists = []; //记录集$lists
    $pk    = $this->getPk();//获取主键
    foreach ($datas as $data) {
        foreach ($data as $key=>$value) {
            if($pk===$key){
                $ids[]=$value;
            }else{
                $lists[$key].= sprintf("WHEN %u THEN '%s' ",$data[$pk],$value);
            }
        }
    }
    foreach ($lists as $key => $value) {
        $sql.= sprintf("`%s` = CASE `%s` %s END,",$key,$pk,$value);
    }
    $sql = sprintf('UPDATE __%s__ SET %s WHERE %s IN ( %s )',strtoupper($model),rtrim($sql,','),$pk,implode(',',$ids));
    return M()->execute($sql);
}

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