时间:2021-07-01 10:21:17 帮助过:21人阅读
break: 此语句导致程序终止包含它的循环,并进行程序的下一阶段(整个循环后面的语句),即,不是跳到下一个循环周期而是退出循环。如果break语句包含在嵌套循环里,它只跳出最里面的循环。
#include<stdio.h> int main() { int res=0; int i=0; int n=0; printf("test break and continue\n"); for(i=0;i<6;i++) { printf("start...\n"); if(i==3) { printf("break \n"); break; printf("break after\n"); //printf("continue \n"); //continue; //printf("continue after\n"); } printf("now i = %d\n",i); } printf("test over !!!\n"); return 0; }
$ gcc -o bc bc.c $ ./bc test break and continue start... now i = 0 start... now i = 1 start... now i = 2 start... break test over !!! $
嵌套循环(break):
#include<stdio.h> int main() { int res=0; int i=0; int n=0; printf("test break and continue\n"); for(i=0;i<6;i++) { printf("start...\n"); for(n=0;n<6;n++) { if(n==3) { printf("break \n"); break; //printf("continue \n"); //continue; } printf("now n= %d\n",n); } if(i==3) { printf("break \n"); break; printf("break after\n"); //printf("continue \n"); //continue; //printf("continue after\n"); } printf("now i = %d\n",i); } printf("test over !!!\n"); return 0; }
$ gcc -o bc bc.c $ ./bc test break and continue start... now n= 0 now n= 1 now n= 2 break now i = 0 start... now n= 0 now n= 1 now n= 2 break now i = 1 start... now n= 0 now n= 1 now n= 2 break now i = 2 start... now n= 0 now n= 1 now n= 2 break break test over !!! $
continue:循环语句里有此语句时,程序运行到此语句时,不在执行循环体里continue后面的语句而是跳到下一个循环入口处执行下一个循环。如果continue语句包含在嵌套循环语句里,它只影响包含它的最里层的循环。
#include<stdio.h> int main() { int res=0; int i=0; int n=0; printf("test break and continue\n"); for(i=0;i<6;i++) { printf("start...\n"); if(i==3) { //printf("break \n"); //break; //printf("break after\n"); printf("continue \n"); continue; printf("continue after\n"); } printf("now i = %d\n",i); } printf("test over !!!\n"); return 0; }
$ gcc -o bc bc.c $ ./bc test break and continue start... now i = 0 start... now i = 1 start... now i = 2 start... continue start... now i = 4 start... now i = 5 test over !!! $
嵌套循环(continue):
#include<stdio.h> int main() { int res=0; int i=0; int n=0; printf("test break and continue\n"); for(i=0;i<6;i++) { printf("start...\n"); for(n=0;n<6;n++) { if(n==3) { //printf("break \n"); //break; printf("continue \n"); continue; } printf("now n= %d\n",n); } if(i==3) { //printf("break \n"); //break; //printf("break after\n"); printf("continue \n"); continue; printf("continue after\n"); } printf("now i = %d\n",i); } printf("test over !!!\n"); return 0; }
$ gcc -o bc bc.c $ ./bc test break and continue start... now n= 0 now n= 1 now n= 2 continue now n= 4 now n= 5 now i = 0 start... now n= 0 now n= 1 now n= 2 continue now n= 4 now n= 5 now i = 1 start... now n= 0 now n= 1 now n= 2 continue now n= 4 now n= 5 now i = 2 start... now n= 0 now n= 1 now n= 2 continue now n= 4 now n= 5 continue start... now n= 0 now n= 1 now n= 2 continue now n= 4 now n= 5 now i = 4 start... now n= 0 now n= 1 now n= 2 continue now n= 4 now n= 5 now i = 5 test over !!! $
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