时间:2021-07-01 10:21:17 帮助过:7人阅读
<?php
function replace(){
$sql = db_query("SELECT field_languages_value,nid FROM {content_type_company_profile} WHERE
field_languages_value like '%Mandarin Chinese%'");
while($result = db_fetch_object($sql)){
$a = explode("Mandarin Chinese",$result->field_languages_used_value);
$b = $a[].'Chinese'.$a[1];
db_query("UPDATE content_type_company_profile SET field_languages_used_value = '%s' WHERE nid = %
d",$b,$result->nid);
}
}
?>