时间:2021-07-01 10:21:17 帮助过:19人阅读
- public class Levenshtein {
- private int compare(String str, String target) {
- int d[][]; // 矩阵
- int n = str.length();
- int m = target.length();
- int i; // 遍历str的
- int j; // 遍历target的
- char ch1; // str的
- char ch2; // target的
- int temp; // 记录相同字符,在某个矩阵位置值的增量,不是0就是1
- if (n == 0) {
- return m;
- }
- if (m == 0) {
- return n;
- }
- d = new int[n + 1][m + 1];
- for (i = 0; i <= n; i++) { // 初始化第一列
- d[i][0] = i;
- }
- for (j = 0; j <= m; j++) { // 初始化第一行
- d[0][j] = j;
- }
- for (i = 1; i <= n; i++) { // 遍历str
- ch1 = str.charAt(i - 1);
- // 去匹配target
- for (j = 1; j <= m; j++) {
- ch2 = target.charAt(j - 1);
- if (ch1 == ch2) {
- temp = 0;
- } else {
- temp = 1;
- }
- // 左边+1,上边+1, 左上角+temp取最小
- d[i][j] = min(d[i - 1][j] + 1, d[i][j - 1] + 1, d[i - 1][j - 1] + temp);
- }
- }
- return d[n][m];
- }
- private int min(int one, int two, int three) {
- return (one = one < two ? one : two) < three ? one : three;
- }
- /**
- * 获取两字符串的相似度
- *
- * @param str
- * @param target
- * @return
- */
- public float getSimilarityRatio(String str, String target) {
- return 1 - (float)compare(str, target)/Math.max(str.length(), target.length());
- }
- public static void main(String[] args) {
- Levenshtein lt = new Levenshtein();
- String str = "1#2203NO525FANGXIEROADHUANGPUDISTRICTSHANGHAICHINA";
- String target = "1#2203NO525FANGXIEROADSHANGHAICN";
- System.out.println("similarityRatio="+ lt.getSimilarityRatio(str, target));
- }
- }
以上就是比较两个字符串的相似度 的内容,更多相关内容请关注PHP中文网(www.gxlcms.com)!