1): echo $name."中包含".$pan; else: echo $name.">
时间:2021-07-01 10:21:17 帮助过:3人阅读
http://www.bkjia.com/PHPjc/318093.htmlwww.bkjia.comtruehttp://www.bkjia.com/PHPjc/318093.htmlTechArticle?php $name="001x.gif"; $pan="x"; $con=explode($pan,$name); if(count($con)1): echo$name."中包含".$pan; else: echo$name."中没有包含".$pan; endif; ?...