phpsession安全问题分析_PHP教程

<br><!--?php <BR-->if(!isset($_SESSION['user_agent'])){ <br>$_SESSION['user_agent'] =$_SERVER['REMOTE_ADDR'].$_SERVER['HTTP_USER_AGENT']; <br>} <br>/* 如果用户session ID是伪造 */ <br>elseif ($_SESSION['user_agent'] != $_SERVER['REMOTE_ADDR'] .$_SERVER['HTTP_USER_AGENT']) { <br>session_regenerate_id(); <br>} <br>?> <br>
<p></p>
<p align="left"><span id="url" itemprop="url">http://www.bkjia.com/PHPjc/323634.html</span><span id="indexUrl" itemprop="indexUrl">www.bkjia.com</span><span id="isOriginal" itemprop="isOriginal">true</span><span id="isBasedOnUrl" itemprop="isBasedOnUrl">http://www.bkjia.com/PHPjc/323634.html</span><span id="genre" itemprop="genre">TechArticle</span><span id="description" itemprop="description">因此,我们主要解决的思路是效验session ID的有效性. 以下为引用的内容：  代码如下:</span></p><pre class="brush:php;toolbar:false layui-box layui-code-view layui-code-notepad"><ol class="layui-code-ol"><li>?php if(!isset($_SESSION['user_agent'])){ $_SESSION['user_a...<p></p></li><li>                    </li></ol></pre>