PHP下使用CURL方式POST数据至API接口的代码_PHP教程

其实，也比较简单，上代码：
代码如下:

$url = 'http://127.0.0.1/test.php';//POST指向的链接
$data = array(
'access_token'=>'thekeyvalue'
);

$json_data = postData($url, $data);
$array = json_decode($json_data,true);
echo '

';print_r($array);      <br><br>    function postData($url, $data)      <br>    {      <br>        $ch = curl_init();      <br>        $timeout = 300;       <br>        curl_setopt($ch, CURLOPT_URL, $url);     <br>        curl_setopt($ch, CURLOPT_REFERER, "http://www.gxlcms.com/");   //构造来路    <br>        curl_setopt($ch, CURLOPT_POST, true);      <br>        curl_setopt($ch, CURLOPT_POSTFIELDS, $data);      <br>        curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);      <br>        curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);      <br>        $handles = curl_exec($ch);      <br>        curl_close($ch);      <br>        return $handles;      <br>    }      <br>?><br><p></p>
<p></p>
<p align="left"><span id="url" itemprop="url">http://www.bkjia.com/PHPjc/326623.html</span><span id="indexUrl" itemprop="indexUrl">www.bkjia.com</span><span id="isOriginal" itemprop="isOriginal">true</span><span id="isBasedOnUrl" itemprop="isBasedOnUrl">http://www.bkjia.com/PHPjc/326623.html</span><span id="genre" itemprop="genre">TechArticle</span><span id="description" itemprop="description">其实，也比较简单，上代码：  代码如下:</span></p><pre class="brush:php;toolbar:false layui-box layui-code-view layui-code-notepad"><ol class="layui-code-ol"><li>?php $url = 'http://127.0.0.1/test.php';//POST指向的链接 $data = array( 'access_token'='thekeyvalue' ); $jso...<p></p></li><li>                    </li></ol></pre>