时间:2021-07-01 10:21:17 帮助过:5人阅读
= (int)['key'
search( , = ()-1 = 0 = [] < [
( = + = (int)(%2 == 1 ? (/2) : /2
( < -1 } ( == [ 1 } ( > [ ? = +1 : = -1 } ( < [ ? = -1 : = +1
= '4', '5', '7', '8', '9', '10', '11', '12'
search(,
( search(, );
这个没考虑非顺序键的数组,主要是方法,如果需要大家可以自己扩展下。
http://www.bkjia.com/PHPjc/440342.htmlwww.bkjia.comtruehttp://www.bkjia.com/PHPjc/440342.htmlTechArticle二分法查找数组是否包含某一元素,兼容正反序,代码实现: ? = (int) ['key' search( , = ( )-1 = 0 = [ ] [ ( = + = (int)( %2 == 1 ? ( /2) : /2 ( -1 } ( == [ 1...