时间:2021-07-01 10:21:17 帮助过:31人阅读
$sql .="values('1','1','name3','1@qq.com','ling','23','0',null,null,'1','2012-10-18 16:25:39','1','1','1','1','1')";
mysql_query($sql) or die('insert data failed cause: '.mysql_error());
$select = "select * from user ";
$result = mysql_query($select) or die('select data failed cause: '.mysql_error());
print_r(mysql_fetch_array($result));
$update = "update user set email = '2@QQ.com' where id =3";
echo $update;
mysql_query($update) or die('update data failed cause: '.mysql_error());
$delete = "delete from user where id = 1";
mysql_query($delete) or die('delete data failed cause: '.mysql_error());
http://www.bkjia.com/PHPjc/477939.htmlwww.bkjia.comtruehttp://www.bkjia.com/PHPjc/477939.htmlTechArticle$dbhost=localhost; $dbuser =admin; $dbpass =; $dbname = lch; $conn = mysql_connect($dbhost,$dbuser,$dbpass,$dbname); if($conn) { echo connect; }else { echo 11111; } mysql_select_db...