时间:2021-07-01 10:21:17 帮助过:2人阅读
upfile.php.
function getname($exname){
$dir = "./uploadfile/";
$i=1;
if(!is_dir($dir)){
mkdir($dir,0777);
}
while(true){
if(!is_file($dir.$i.".".$exname)){
$name=$i.".".$exname;
break;
}
$i++;
}
return $dir.$name;
}
$exname=strtolower(substr($_FILES['upfile']['name'],(strrpos($_FILES['upfile']['name'],'.')+1)));
$uploadfile = getname($exname);
if (move_uploaded_file($_FILES['upfile']['tmp_name'], $uploadfile)) {
echo "
}else {
echo "
} echo "下面是文件上传的一些信息:
原文件名:".$_FILES['upfile']['name'] ."
类型:" .$_FILES['upfile']['type'] ."
临时文件名:".$_FILES['upfile']['tmp_name']. "
文件大小:".$_FILES['upfile']['size']."
错误代码:".$_FILES['upfile']['error'];
?>
http://www.bkjia.com/PHPjc/478086.htmlwww.bkjia.comtruehttp://www.bkjia.com/PHPjc/478086.htmlTechArticlehtml head meta http-equiv=Content-Type content=text/html; charset=gb2312 title网页教学网(webjx.com)文件上传实例/title /head body form enctype=multipart/form-data action=...