用php实现备份数据库ZIP及导出_PHP教程

一）

Java代码
1. 2.
3. $username = "root";
4. $password = "";
5. $hostname = "localhost";
6. $dbname = "test";
7.
8.
9. $dumpfname = $dbname . "_" . date("Y-m-d_H-i-s").".sql";
10. $command = "C:\\xampp\\mysql\\bin\\mysqldump --add-drop-table --host=$hostname
11. --user=$username ";
12. if ($password)
13. $command.= "--password=". $password ." ";
14. $command.= $dbname;
15. $command.= " > " . $dumpfname;
16. system($command);
17.
18. // zip 数据文件
19. $zipfname = $dbname . "_" . date("Y-m-d_H-i-s").".zip";
20. $zip = new ZipArchive();
21. if($zip->open($zipfname,ZIPARCHIVE::CREATE))
22. {
23. $zip->addFile($dumpfname,$dumpfname);
24. $zip->close();
25. }
26.
27. // read zip file and send it to standard output
28. if (file_exists($zipfname)) {
29. header('Content-Description: File Transfer');
30. header('Content-Type: application/octet-stream');
31. header('Content-Disposition: attachment; filename='.basename($zipfname));
32. flush();
33. readfile($zipfname);
34. exit;
35. }
36. ?>

方法2 文件夹没相关权限
Java代码
1. 2. ob_start();
3.
4. $username = "root";
5. $password = "";
6. $hostname = "localhost";
7. $dbname = "test";
8.
9. $command = "C:\\xampp\\mysql\\bin\\mysqldump --add-drop-table --host=$hostname
10. --user=$username ";
11. if ($password)
12. $command.= "--password=". $password ." ";
13. $command.= $dbname;
14. system($command);
15.
16. $dump = ob_get_contents();
17. ob_end_clean();
18.
19.
20. //不ZIP了
21. header('Content-Description: File Transfer');
22. header('Content-Type: application/octet-stream');
23. header('Content-Disposition: attachment; filename='.basename($dbname . "_" .
24. date("Y-m-d_H-i-s").".sql"));
25. flush();
26. echo $dump;
27. exit();]]>
28. ?>

http://www.bkjia.com/PHPjc/478285.htmlwww.bkjia.comtruehttp://www.bkjia.com/PHPjc/478285.htmlTechArticle经常在有的PHP开源系统中，看到有备份数据库并导出的方法，其实代码不复杂，下面 大概讲解下，以WINDOWS为例子，两类方法，一个是目录...