ajaxphp用户无刷新登录实例_PHP教程

userlogin.php文件

$uid = $_post['uname'];
$pwd = $_post['upwd'];
$sql ="select * from tabname where uid='$uid' and pwd='$pwd'";
$query = mysql教程_query( $sql );
if( mysql_num_rows( $query ) )
{
echo '登录成功';
}
else
{
echo '用户名或密码不正确!';
}
?>

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