当前位置:Gxlcms > PHP教程 > PHP解析URL并得到URL中的参数_PHP教程

PHP解析URL并得到URL中的参数_PHP教程

时间:2021-07-01 10:21:17 帮助过:3人阅读

$param)
    {
        $tmp[] = $k.'='.$param;
    }
    $params = implode('&',$tmp);
    return $params;
}
?>

输出结果:

array (size=4)
  'scheme' => string 'http' (length=4)
  'host' => string 'test.com' (length=8)
  'path' => string '/testdir/index.php' (length=18)
  'query' => string 'param1=10¶m2=20¶m3=30¶m4=40¶m5=50¶m6=60' (length=59)


array (size=6)
  'param1' => string '10' (length=2)
  'param2' => string '20' (length=2)
  'param3' => string '30' (length=2)
  'param4' => string '40' (length=2)
  'param5' => string '50' (length=2)
  'param6' => string '60' (length=2)


string 'param1=10¶m2=20¶m3=30¶m4=40¶m5=50¶m6=60' (length=59)


www.bkjia.comtruehttp://www.bkjia.com/PHPjc/755760.htmlTechArticle$param) { $tmp[] = $k.'='.$param; } $params = implode('',$tmp); return $params;}?> 输出结果: array (size=4) 'scheme' => string 'http' (length=4) 'host' => string 'test.com' (...

人气教程排行