PHP遍历目录返回统计目录大小实例_PHP教程

php 
$dirname = "test1"; 
//mkdir($dirname);

//遍历一层目录 
function listdir($dirname) { 
$ds = opendir($dirname); 
while($file = readdir($ds)) { 
$path = $dirname.'/'.$file; 
if(is_dir($file)) { 
echo "DIR:".$file."
"; 
if($file != "." && $file != "..") { 
listdir($file); 
} 
} 
else { 
echo "FILE:".$file . "
"; 
} 
} 
}

function totdir($dirname) { //对listdir稍加修改 
static $tot = 0; 
$ds = opendir($dirname); 
while($file = readdir($ds)) { 
$path = $dirname.'/'.$file; 
if(is_dir($file)) { 
//echo "DIR:".$file."
"; 
if($file != "." && $file != "..") { 
$tot += totdir($file); 
} 
} www.jbxue.com
else { 
//echo "FILE:".$file . "
"; 
$tot += filesize($path); 
} 
}

//返回总计 
return $tot; 
}

listdir($dirname);

echo totdir($dirname)." bytes";

?>

http://www.bkjia.com/PHPjc/781159.htmlwww.bkjia.comtruehttp://www.bkjia.com/PHPjc/781159.htmlTechArticle分享一个 PHP遍历目录并返回统计目录大小的方法。 代码： ? php $dirname = "test1" ; // mkdir($dirname);//遍历一层目录 function listdir( $dirname ) { $ds...