时间:2021-07-01 10:21:17 帮助过:1人阅读
本文实例讲述了php比较相似字符串的方法。分享给大家供大家参考。具体分析如下:
这里通过php的similar_text函数比较两个字符串的相似性。
$word2compare = "stupid"; $words = array( 'stupid', 'stu and pid', 'hello', 'foobar', 'stpid', 'upid', 'stuuupid', 'sstuuupiiid', ); while(list($id, $str) = each($words)){ similar_text($str, $word2compare, $percent); print "Comparing '$word2compare' with '$str': "; print round($percent) . "%\n"; } /* Results: Comparing 'stupid' with 'stupid': 100% Comparing 'stupid' with 'stu and pid': 71% Comparing 'stupid' with 'hello': 0% Comparing 'stupid' with 'foobar': 0% Comparing 'stupid' with 'stpid': 91% Comparing 'stupid' with 'upid': 80% Comparing 'stupid' with 'stuuupid': 86% Comparing 'stupid' with 'sstuuupiiid': 71% */
希望本文所述对大家的php程序设计有所帮助。
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