时间:2021-07-01 10:21:17 帮助过:11人阅读
本文实例讲述了PHP将二维数组某一个字段相同的数组合并起来的方法。分享给大家供大家参考,具体如下:
例子:
array(3) { [0]=> array(16) { ["id"]=> string(2) "42" ["uid"]=> string(2) "14" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1443927600" ["createtime"]=> string(10) "1443880619" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月04日" ["date"]=> string(6) "周日" ["uname"]=> NULL ["album"]=> string(0) "" } [1]=> array(16) { ["id"]=> string(2) "40" ["uid"]=> string(2) "14" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1444359600" ["createtime"]=> string(10) "1444268595" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月09日" ["date"]=> string(6) "周五" ["uname"]=> NULL ["album"]=> string(0) "" } [2]=> array(16) { ["id"]=> string(2) "43" ["uid"]=> string(1) "2" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1444359620" ["createtime"]=> string(10) "1444268595" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月09日" ["date"]=> string(6) "周五" ["uname"]=> NULL ["album"]=> string(0) "" } }
现在想要对这个二维数组下的元素,time相同的合并到同一数组下。想要的效果为:
array(2) { ["10月04日"]=> array(1) { [0]=> array(16) { ["id"]=> string(2) "42" ["uid"]=> string(2) "14" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1443927600" ["createtime"]=> string(10) "1443880619" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月04日" ["date"]=> string(6) "周日" ["uname"]=> NULL ["album"]=> string(0) "" } } ["10月09日"]=> array(2) { [0]=> array(16) { ["id"]=> string(2) "40" ["uid"]=> string(2) "14" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1444359600" ["createtime"]=> string(10) "1444268595" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月09日" ["date"]=> string(6) "周五" ["uname"]=> NULL ["album"]=> string(0) "" } [1]=> array(16) { ["id"]=> string(2) "43" ["uid"]=> string(1) "2" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1444359620" ["createtime"]=> string(10) "1444268595" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月09日" ["date"]=> string(6) "周五" ["uname"]=> NULL ["album"]=> string(0) "" } } }
那么。。。代码很简单,没有想象的那么复杂,想要的结果是个三维数组
$result 为原二维数组
$res = array(); //想要的结果 foreach ($result as $k => $v) { $res[$v['time']][] = $v; }
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