还是问一个mysql的查询汇总的汇总问题

id  uid  scroe-------------1    1    1.52    1    1.83    2    -5.54    1    0.85    2    8.26    1    -27    4    38    2    2.3--------------

用户  分数   汇总分-----------------------1      1.5     2.11      1.8     2.11      0.8     2.11      -2      2.12      -5.5    52      8.2     52      2.3     53      0       04      3       35      0       0

回复讨论(解决方案)

不知道楼主想要问什么

怎么得到第二张表，mysql语句怎么写？

建表：

CREATE TABLE a	(`id` int, `uid` int, `scroe` float);	INSERT INTO a	(`id`, `uid`, `scroe`)VALUES	(1, 1, 1.5),	(2, 1, 1.8),	(3, 2, -5.5),	(4, 1, 0.8),	(5, 2, 8.2),	(6, 1, -2),	(7, 4, 3),	(8, 2, 2.3);

问题是你数据集里都没uid=3和uid=5的纪录。参考

select t.*,round(s.scroe,1) as scroe , round(if(s.total is null,0,s.total),1) as summary from (select 1 as uid union select 2 as uidunionselect 3 as uid union select 4 as uidunion select 5 as uid) t left join (select uid,scroe,(select sum(scroe) from a where uid=aa.uid group by uid) as total from a as aa) son s.uid = t.uid

问题是你数据集里都没uid=3和uid=5的纪录。

uid是和user表里管理的字段，根据user表里的记录来读取：
在这里： http://bbs.csdn.net/topics/390673185

用户表tu

得分表t

SQL：SELECT tu.uid,t.score,a.total from test t right join test_user tu on tu.uid=t.uid left join (SELECT uid,sum(score) as total from test group by uid) a on a.uid=t.uid order by tu.uid

结果