PHP+MYSQL多关键词+模糊搜索+匹配度排序，请教怎么实现？

回复讨论(解决方案)

将你的表结构贴和sql贴出来

本帖最后由 xuzuning 于 2013-02-23 10:18:55 编辑

(SELECT a.`askid`,a.`catid`,a.`title`,a.`status`,a.`addtime`,a.`reward`,a.`answercount`,b.`message` FROM `phpcms_ask` a LEFT JOIN `phpcms_ask_posts` b ON a.`askid`=b.`askid` WHERE (a.status=3 OR a.status=5) AND (LOCATE('中国北京天安门',a.`title`)>0) AND b.`isask`=1)UNION (SELECT a.`askid`,a.`catid`,a.`title`,a.`status`,a.`addtime`,a.`reward`,a.`answercount`,b.`message` FROM `phpcms_ask` a LEFT JOIN `phpcms_ask_posts` b ON a.`askid`=b.`askid` WHERE (a.status=3 OR a.status=5) AND (LOCATE('中国',a.`title`)>0 AND LOCATE('北京',a.`title`)>0 AND LOCATE('天安门',a.`title`)>0) AND b.`isask`=1) UNION (SELECT a.`askid`,a.`catid`,a.`title`,a.`status`,a.`addtime`,a.`reward`,a.`answercount`,b.`message` FROM `phpcms_ask` a LEFT JOIN `phpcms_ask_posts` b ON a.`askid`=b.`askid` WHERE (a.status=3 OR a.status=5) AND (LOCATE('中国',a.`title`)>0 AND LOCATE('北京',a.`title`)>0) AND b.`isask`=1)UNION(SELECT a.`askid`,a.`catid`,a.`title`,a.`status`,a.`addtime`,a.`reward`,a.`answercount`,b.`message` FROM `phpcms_ask` a LEFT JOIN `phpcms_ask_posts` b ON a.`askid`=b.`askid` WHERE (a.status=3 OR a.status=5) AND (LOCATE('北京',a.`title`)>0 AND LOCATE('天安门',a.`title`)>0) AND b.`isask`=1)UNION(SELECT a.`askid`,a.`catid`,a.`title`,a.`status`,a.`addtime`,a.`reward`,a.`answercount`,b.`message` FROM `phpcms_ask` a LEFT JOIN `phpcms_ask_posts` b ON a.`askid`=b.`askid` WHERE (a.status=3 OR a.status=5) AND (LOCATE('中国',a.`title`)>0 OR LOCATE('北京',a.`title`)>0 OR LOCATE('天安门',a.`title`)>0) AND b.`isask`=1)LIMIT 0,20

phpcms_ask表: askid catid title tags reward userid username addtime endtime status flag answercount anonymity hits ischeck


phpcms_ask_posts表：pid askid isask message addtime reply rptime candidate optimal reversion userid status anonymity username

既然你不需要计算出现的次数，那么合起来不是更好

SELECT a.`askid`,a.`catid`,a.`title`,a.`status`,a.`addtime`,a.`reward`,a.`answercount`,b.`message`  FROM `phpcms_ask` a LEFT JOIN `phpcms_ask_posts` b ON a.`askid`=b.`askid` WHERE (a.status=3 OR a.status=5) AND b.`isask`=1 AND (LOCATE('中国',a.`title`)>0 OR LOCATE('北京',a.`title`)>0 OR LOCATE('天安门',a.`title`)>0)

若要计算匹配度，也只需
select sign(LOCATE('中国',a.`title`))+sign(LOCATE('北京',a.`title`))+sign(LOCATE('天安门',a.`title`)) as 匹配数 from ...

既然你不需要计算出现的次数，那么合起来不是更好
SQL code?123SELECT a.`askid`,a.`catid`,a.`title`,a.`status`,a.`addtime`,a.`reward`,a.`answercount`,b.`message` FROM `phpcms_ask` a LEFT JOIN `phpcms_ask_posts` b……

感谢版主，您的方法非常有效！！现在速度快了很多。

匹配度排序该如何实现呢

若要计算匹配度，也只需
select sign(LOCATE('中国',a.`title`))+sign(LOCATE('北京',a.`title`))+sign(LOCATE('天安门',a.`title`)) as 匹配数 from ...

版主 请问：按指定的??字在字段中出?的次?排序 该如何实现呢？ 只在一个字段中查询