数组针对某项的求和问题

已知数组a：

array (  0 =>   array (    'stock_no' => 'SU13080800340',    'adress' => 'B',    'arr_time' => '2013-08-14 09:00:00',    'c_type' => 'P32E',    'cust_no' => '310F61VA5A',    'mount_total' => '1',    'total' => '16',    'c1_time' => '2013-08-10 15:00:00',    'packageno' => 'CVT121015001',  ),  1 =>   array (    'stock_no' => 'SU13080800340',    'adress' => 'B',    'arr_time' => '2013-08-14 09:00:00',    'c_type' => 'P32E',    'cust_no' => '310F61VA5B',    'mount_total' => '2',    'total' => '32',    'c1_time' => '2013-08-10 15:00:00',    'packageno' => 'CVT121015002',  ),  2 =>   array (    'stock_no' => 'SU13080800340',    'adress' => 'B',    'arr_time' => '2013-08-14 09:00:00',    'c_type' => 'P32E',    'cust_no' => '310F61VA5B',    'mount_total' => '2',    'total' => '32',    'c1_time' => '2013-08-10 15:00:00',    'packageno' => 'CVT121226001',  ),)

如何分别求得数组中的项cust_no对应的packageno的结果以及stock_no对应mount_total和total项求和的结果？
假设cust_no为310F61VA5A时，对应的packageno为CVT121225001。
cust_no为310F61VA5B时，对应的packageno为CVT121225002，CVT121226001。

stock_no为SU13080800340时，求得的mount_total结果为3（1+2），total结果为48（16+32）。

如何达到这样的效果？

回复讨论(解决方案)

	$a = array (   0 =>    array (     'stock_no' => 'SU13080800340',     'adress' => 'B',     'arr_time' => '2013-08-14 09:00:00',     'c_type' => 'P32E',     'cust_no' => '310F61VA5A',     'mount_total' => '1',     'total' => '16',     'c1_time' => '2013-08-10 15:00:00',     'packageno' => 'CVT121015001',   ),   1 =>    array (     'stock_no' => 'SU13080800340',     'adress' => 'B',     'arr_time' => '2013-08-14 09:00:00',     'c_type' => 'P32E',     'cust_no' => '310F61VA5B',     'mount_total' => '2',     'total' => '32',     'c1_time' => '2013-08-10 15:00:00',     'packageno' => 'CVT121015002',   ),   2 =>    array (     'stock_no' => 'SU13080800340',     'adress' => 'B',     'arr_time' => '2013-08-14 09:00:00',     'c_type' => 'P32E',     'cust_no' => '310F61VA5B',     'mount_total' => '2',     'total' => '32',     'c1_time' => '2013-08-10 15:00:00',     'packageno' => 'CVT121226001',   ), );function foo1($cust_no,$a=array()){	foreach($a as $each){		if($each['cust_no'] == $cust_no){			$res[] = $each['packageno'];		}	}	if($res){		return implode(",",$res);	}else{		return false;	}}function foo2($stock_no,$a=array()){	foreach($a as $each){		if($each['stock_no'] == $stock_no){			$mount_total[] = $each['mount_total'];			$total[] = $each['total'];		}	}	$mount_total = array_unique($mount_total);		//去重复	$total = array_unique($total);	$res['mount_total'] = array_sum($mount_total);	$res['total'] = array_sum($total);	return $res;}var_export(foo1("310F61VA5B",$a));var_export(foo2("SU13080800340",$a));

'CVT121015002,CVT121226001'
array ( 'mount_total' => 3, 'total' => 48, )

$ar=array (  0 =>   array (    'stock_no' => 'SU13080800340',    'adress' => 'B',    'arr_time' => '2013-08-14 09:00:00',    'c_type' => 'P32E',    'cust_no' => '310F61VA5A',    'mount_total' => '1',    'total' => '16',    'c1_time' => '2013-08-10 15:00:00',    'packageno' => 'CVT121015001',  ),  1 =>   array (    'stock_no' => 'SU13080800340',    'adress' => 'B',    'arr_time' => '2013-08-14 09:00:00',    'c_type' => 'P32E',    'cust_no' => '310F61VA5B',    'mount_total' => '2',    'total' => '32',    'c1_time' => '2013-08-10 15:00:00',    'packageno' => 'CVT121015002',  ),  2 =>   array (    'stock_no' => 'SU13080800340',    'adress' => 'B',    'arr_time' => '2013-08-14 09:00:00',    'c_type' => 'P32E',    'cust_no' => '310F61VA5B',    'mount_total' => '2',    'total' => '32',    'c1_time' => '2013-08-10 15:00:00',    'packageno' => 'CVT121226001',  ),);foreach($ar as $v){    $a[$v['cust_no']][]=$v['packageno'];	$b[$v['stock_no']][]=$v['mount_total'];	$c[$v['stock_no']][]=$v['total'];}print_r($a);print_r($b);print_r($c);

Array
(
[310F61VA5A] => Array
(
[0] => CVT121015001
)

[310F61VA5B] => Array
(
[0] => CVT121015002
[1] => CVT121226001
)

)
Array
(
[SU13080800340] => Array
(
[0] => 1
[1] => 2
[2] => 2
)

)
Array
(
[SU13080800340] => Array
(
[0] => 16
[1] => 32
[2] => 32
)

)

第一个问题 循环数组 判断每一个cust_no字段的值为给定值的数组元素的packageno的值加起来 就是你要的结果.

第二个问题 循环数组 判断每一个stock_no字段的值为给定值的数组元素的两个要求字段的值存入数组,循环结束后分别去除重复的然后相加

$a = array (  0 =>   array (    'stock_no' => 'SU13080800340',    'adress' => 'B',    'arr_time' => '2013-08-14 09:00:00',    'c_type' => 'P32E',    'cust_no' => '310F61VA5A',    'mount_total' => '1',    'total' => '16',    'c1_time' => '2013-08-10 15:00:00',    'packageno' => 'CVT121015001',  ),  1 =>   array (    'stock_no' => 'SU13080800340',    'adress' => 'B',    'arr_time' => '2013-08-14 09:00:00',    'c_type' => 'P32E',    'cust_no' => '310F61VA5B',    'mount_total' => '2',    'total' => '32',    'c1_time' => '2013-08-10 15:00:00',    'packageno' => 'CVT121015002',  ),  2 =>   array (    'stock_no' => 'SU13080800340',    'adress' => 'B',    'arr_time' => '2013-08-14 09:00:00',    'c_type' => 'P32E',    'cust_no' => '310F61VA5B',    'mount_total' => '2',    'total' => '32',    'c1_time' => '2013-08-10 15:00:00',    'packageno' => 'CVT121226001',  ),);$res = array();foreach($a as $item) {  if(! isset($res[$item['stock_no']][$item['cust_no']])) {    $res[$item['stock_no']][$item['cust_no']] = $item;  }else {    $res[$item['stock_no']][$item['cust_no']]['mount_total'] += $item['mount_total'];    $res[$item['stock_no']][$item['cust_no']]['total'] += $item['total'];    $res[$item['stock_no']][$item['cust_no']]['packageno'] .= ',' .$item['packageno'];  }}foreach($res as &$item) $item = array_values($item);print_r($res);

Array
(
[SU13080800340] => Array
(
[0] => Array
(
[stock_no] => SU13080800340
[adress] => B
[arr_time] => 2013-08-14 09:00:00
[c_type] => P32E
[cust_no] => 310F61VA5A
[mount_total] => 1
[total] => 16
[c1_time] => 2013-08-10 15:00:00
[packageno] => CVT121015001
)

[1] => Array
(
[stock_no] => SU13080800340
[adress] => B
[arr_time] => 2013-08-14 09:00:00
[c_type] => P32E
[cust_no] => 310F61VA5B
[mount_total] => 4
[total] => 64
[c1_time] => 2013-08-10 15:00:00
[packageno] => CVT121015002,CVT121226001
)

)

)

[code=php]
Array
(
[310F61VA5A] => Array
(
[0] => CVT121015001
)

[310F61VA5B] => Array
(
[0] => CVT121015002
[1] => CVT121226001
)

)
Array
(
[SU13080800340] => Array
(
[0] => 1
[1] => 2
[2] => 2
)

)
Array
(
[SU13080800340] => Array
(
[0] => 16
[1] => 32
[2] => 32
)

)

第一项OK，但是mount_total和total的求和结果不对，我要的是stock_no为SU13080800340时，求得的mount_total结果为3（1+2），total结果为48（16+32）。

$res = array();foreach($a as $item) {  if(! isset($res[$item['stock_no']][$item['cust_no']])) {    $res[$item['stock_no']][$item['cust_no']] = $item;  }else {    $res[$item['stock_no']][$item['cust_no']]['mount_total'] += $item['mount_total'];    $res[$item['stock_no']][$item['cust_no']]['total'] += $item['total'];    $res[$item['stock_no']][$item['cust_no']]['packageno'] .= ',' .$item['packageno'];  }}foreach($res as &$item) $item = array_values($item);print_r($res);

我想要得到的stockno的求和结果是mount_total为3（2+1），total结果为48（16+32）。

楼主这种问题 应该算是比较基础的 我有点好奇为什么会纠结于
Array
(
[0] => 16
[1] => 32
[2] => 32
)
这种数组的加和? 你的需求应该是去了重复求和.... 一个PHP函数的事情...

你的数组中三个stock_no的值不是一样的吗，都为 SU13080800340 吧，难道我眼花了？

那是你的数据给错了
'cust_no' => '310F61VA5A',
'mount_total' => '1',
'total' => '16',

'cust_no' => '310F61VA5B',
'mount_total' => '2',
'total' => '32',

'cust_no' => '310F61VA5B',
'mount_total' => '2',
'total' => '32',

那是你的数据给错了
'cust_no' => '310F61VA5A',
'mount_total' => '1',
'total' => '16',

'cust_no' => '310F61VA5B',
'mount_total' => '2',
'total' => '32',

'cust_no' => '310F61VA5B',
'mount_total' => '2',
'total' => '32',
那我再想想。

你的数组中三个stock_no的值不是一样的吗，都为 SU13080800340 吧，难道我眼花了？
那怎么去重复求和呢？

那是你的数据给错了
'cust_no' => '310F61VA5A',
'mount_total' => '1',
'total' => '16',

'cust_no' => '310F61VA5B',
'mount_total' => '2',
'total' => '32',

'cust_no' => '310F61VA5B',
'mount_total' => '2',
'total' => '32',
如果是去重复求和呢？

那是你的数据给错了
'cust_no' => '310F61VA5A',
'mount_total' => '1',
'total' => '16',

'cust_no' => '310F61VA5B',
'mount_total' => '2',
'total' => '32',

'cust_no' => '310F61VA5B',
'mount_total' => '2',
'total' => '32',
如果是去重复求和呢？

去重复求和 抬头看看一楼....