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已知日期:2013-07-31加12个月3个月1个月得到相应的日期

时间:2021-07-01 10:21:17 帮助过:10人阅读

已知日期:2013-07-31 加12个月 3个月 1个月 得到相应的日期

求大牛怎么写PHP代码?


回复讨论(解决方案)


$date1="2006-08-09";
echo date('Y-m-d',strtotime("$date1 +5 day")); //相应地,要增加月,年,将day改成month或year即可
?>
输出结果:2006-08-14

+++++++++++++ 今天、昨天、明天 、上一周、下一周 +++++++++++++++

date_default_timezone_set('PRC'); //默认时区
echo "今天:",date("Y-m-d",time()),"
";
echo "昨天:",date("Y-m-d",strtotime("-1 day")), "
";
echo "明天:",date("Y-m-d",strtotime("+1 day")), "
";
echo "一周后:",date("Y-m-d",strtotime("+1 week")), "
";
echo "一周零两天四小时两秒后:",date("Y-m-d G:H:s",strtotime("+1 week 2 days 4 hours 2 seconds")), "
";
echo "下个星期四:",date("Y-m-d",strtotime("next Thursday")), "
";
echo "上个周一:".date("Y-m-d",strtotime("last Monday"))."
";
echo "一个月前:".date("Y-m-d",strtotime("last month"))."
";
echo "一个月后:".date("Y-m-d",strtotime("+1 month"))."
";
echo "十年后:".date("Y-m-d",strtotime("+10 year"))."
";

?>


$date1="2006-08-09";
echo date('Y-m-d',strtotime("$date1 +5 day")); //相应地,要增加月,年,将day改成month或year即可
?>
输出结果:2006-08-14

+++++++++++++ 今天、昨天、明天 、上一周、下一周 +++++++++++++++

date_default_timezone_set('PRC'); //默认时区
echo "今天:",date("Y-m-d",time()),"
";
echo "昨天:",date("Y-m-d",strtotime("-1 day")), "
";
echo "明天:",date("Y-m-d",strtotime("+1 day")), "
";
echo "一周后:",date("Y-m-d",strtotime("+1 week")), "
";
echo "一周零两天四小时两秒后:",date("Y-m-d G:H:s",strtotime("+1 week 2 days 4 hours 2 seconds")), "
";
echo "下个星期四:",date("Y-m-d",strtotime("next Thursday")), "
";
echo "上个周一:".date("Y-m-d",strtotime("last Monday"))."
";
echo "一个月前:".date("Y-m-d",strtotime("last month"))."
";
echo "一个月后:".date("Y-m-d",strtotime("+1 month"))."
";
echo "十年后:".date("Y-m-d",strtotime("+10 year"))."
";

?>
这个不行。要加自然月,有的月分28天。有的31天

$s='2013-07-31';
echo date("Y-m-d",strtotime("$s+1 month"));

呵呵,想当然了

echo date("Y-m-d\n",strtotime("$s+7 month"));
得到 2014-03-03
select adddate('2013-07-31', INTERVAL 7 month)
得到 2014-02-28

显然,php 的表现是不尽人意的

mktime其实也可以达到要求

$t = '2013-07-31';echo date("Y-m-d",mktime(0,0,0,date("m") + 12,date("d") , date("Y"))).'
';echo date("Y-m-d",mktime(0,0,0,date("m") + 3,date("d") , date("Y"))).'
';echo date("Y-m-d",mktime(0,0,0,date("m") + 1,date("d") , date("Y"))).'
';



结果:
2014-07-312013-10-312013-08-31

$t = '2013-07-31';echo date("Y-m-d",mktime(0,0,0,date("m") + 2,date("d") , date("Y")));

得 2013-10-01

最要不得的是:回避矛盾

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