求大神解答一个数据库语句的问题

SELECT `id` , `time` , `title`FROM `think_infor`WHERE `type` LIKE '$k-%'			UNION ALL			SELECT `id` , `time` , `title`FROM `think_infor2`WHERE `type` LIKE '$k-%'			ORDER BY `time` DESCLIMIT 0,6

回复讨论(解决方案)

你带上表名不就行了？

不过你能得到 表1和表2的最新6条信息 吗？

SELECT A.id AS aid , A.time AS atime , A.title AS atitle, B.id AS bid , B.time AS btime , B.title AS btitle
FROM think_infor AS A, think_infor2 AS B
WHERE A.type LIKE '$k-%' AND B.type=A.type
ORDER BY A.time DESC LIMIT 0,6

SELECT A.id AS aid , A.time AS atime , A.title AS atitle, B.id AS bid , B.time AS btime , B.title AS btitle
FROM think_infor AS A, think_infor2 AS B
WHERE A.type LIKE '$k-%' AND B.type=A.type
ORDER……


这个差不多，但是A表的记录是会有重复记录

SELECT `id` , `time` , `title`, 1 as cpfromFROM `think_infor`WHERE `type` LIKE '$k-%'			UNION ALL			SELECT `id` , `time` , `title` , 2 as cpfromFROM `think_infor2`WHERE `type` LIKE '$k-%'			ORDER BY `time` DESCLIMIT 0,6

这个语句写的不是很清楚

引用 2 楼 yiwusuo 的回复:SELECT A.id AS aid , A.time AS atime , A.title AS atitle, B.id AS bid , B.time AS btime , B.title AS btitle
FROM think_infor AS A, think_infor2 AS B
WHERE A.type LIKE……
ORDER BY A.time DESC 后面加上：having count(A.id)=1
不就没重复了吗

我自己都觉得乱了，我还是说一下我想要的东西吧


有A表，B表，结构相同，数据不同，我想同时模糊查询一个字段`type`，选取两表中符合条件的前6条记录(根据`time`排序)

你自己写的不就可以吗？

SELECT `id` , `time` , `title`, 'think_infor' as tbl_name  FROM `think_infor`  WHERE `type` LIKE '$k-%'UNIONSELECT `id` , `time` , `title`, 'think_infor2'   FROM `think_infor2`  WHERE `type` LIKE '$k-%'ORDER BY `time` DESCLIMIT 0,6

你自己写的不就可以吗？


SQL code
?



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SELECT `id` , `time` , `title`, 'think_infor' as tbl_name FROM `think_infor` WHERE `type` LIKE '$k-%'UNIONSELECT `id` , `time` , `title`, 'think_in……

SELECT 不存在的字段这也可以

你是指 'think_infor' as tbl_name 这个吗？

那么你认为 SELECT `id` as iidd FROM `think_infor` 这样可以吗？
肯定可以了，不就是给个名字么

接下来就不说了