mysql_query()不能正常解析sql

		INSERT INTO analysis.caomei_of_list_pvuv  									(region,isp,uv,pv,date)  									SELECT										tb2.region,tb2.isp,tb2.uv,tb2.pv,'2014-05-14' AS date   									FROM   									(										SELECT 											tb.region,tb.isp, COUNT(tb.mac) AS uv,											SUM(tb.mac_num) AS pv  										FROM 											caomei_20140515.caomei_1 AS tb 										WHERE 											tb.date = '2014-05-14'  										GROUP BY tb.region, tb.isp 									) AS tb2  									LEFT JOIN 									(										SELECT 											tb6.region,tb6.isp,tb6.uv,tb6.pv 										FROM 											analysis.caomei_of_list_pvuv AS tb6 										WHERE 											tb6.date='2014-05-14'   									) AS tb1 																				ON tb2.region = tb1.region 									WHERE 										tb1.region IS NULL  										AND tb2.region IS NOT NULL 									;

回复讨论(解决方案)

NSERT INTO analysis.caomei_of_list_pvuv
(region,isp,uv,pv,date)
SELECT
tb2.region,tb2.isp,tb2.uv,tb2.pv,'2014-05-14' AS date
FROM
(
SELECT
tb.region,tb.isp, COUNT(tb.mac) AS uv,
SUM(tb.mac_num) AS pv
FROM
caomei_20140515.caomei_1 AS tb
WHERE
tb.date = '2014-05-14'
GROUP BY tb.region, tb.isp
) AS tb2
LEFT JOIN
(
SELECT
tb6.region,tb6.isp,tb6.uv,tb6.pv
FROM
analysis.caomei_of_list_pvuv AS tb6
WHERE
tb6.date='2014-05-14'
) AS tb1

ON tb2.region = tb1.region
WHERE
tb1.region IS NULL
AND tb2.region IS NOT NULL

这是不允许的

NSERT INTO analysis.caomei_of_list_pvuv
(region,isp,uv,pv,date)
SELECT
tb2.region,tb2.isp,tb2.uv,tb2.pv,'2014-05-14' AS date
FROM
(
SELECT
tb.region,tb.isp, COUNT(tb.mac) AS uv,
SUM(tb.mac_num) AS pv
FROM
caomei_20140515.caomei_1 AS tb
WHERE
tb.date = '2014-05-14'
GROUP BY tb.region, tb.isp
) AS tb2
LEFT JOIN
(
SELECT
tb6.region,tb6.isp,tb6.uv,tb6.pv
FROM
analysis.caomei_of_list_pvuv AS tb6
WHERE
tb6.date='2014-05-14'
) AS tb1

ON tb2.region = tb1.region
WHERE
tb1.region IS NULL
AND tb2.region IS NOT NULL

这是不允许的

问题不在于是否有语法错
而在于控制逻辑是循环悖论

但我觉得这样应该没有逻辑问题啊，先查出结果。然后将结果写入自己。
最主要是 php运行的结果和mysql运行的结果不同！！

是要尽量避免这种逻辑吗，否则就会出现这种意想不到的结果啊

INSERT INTO a (version)SELECT version FROM a WHERE id=1;

假定第一次执行插入了 1 条
那么第二次执行就会插入 2 条
第三次执行就会插入 4 条

我知道了。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。。