算法题。

对象原有属性值全部是大写，需求是将对象的属性值全部转化成小写么。 通常思路是  对象转化成数组（遍历转化成小写）再转化成对象  这样的思路很繁琐递归数据源且效率低求高效思路或方法stdClass Object(    [INFO] => stdClass Object        (            [A] => 1            [B] => 2            [C] => 3            [C] => 4            [D] => stdClass Object                (                    [AA] => 11                    [BB] => 22                    [CC] => 33                    [CC] => 44                )        ))

回复讨论(解决方案)

对象不可能出现同名属性，请调整一下

对象不可能出现同名属性，请调整一下

stdClass Object(    [INFO] => stdClass Object        (            [A] => 1            [B] => 2            [C] => 3            [D] => stdClass Object                (                    [AA] => 11                    [BB] => 22                    [CC] => 33                    [CC] => 44                )         ) )

转化为数组了过后可以用spl中的数组迭代器来遍历，不知道速度会不会快一点

不是很明白为什么要有这样的需求，可以这样写

$s = '{"A":1,"B":2,"C":3,"D":{"AA":11,"BB":22,"CC":33}}';$o = json_decode($s); //模拟一个对象$t = serialize($o);$t = preg_replace_callback('/("[A-Z]+")(;.+?;)/', function($r) { return strtolower($r[1]) . $r[2]; }, $t);$o = unserialize($t);print_r($o);

stdClass Object(    [a] => 1    [b] => 2    [c] => 3    [d] => stdClass Object        (            [aa] => 11            [bb] => 22            [cc] => 33        ))

$s = '{"A":1,"B":2,"C":3,"D":{"AA":11,"BB":22,"CC":33}}';$s = preg_replace_callback('/"[A-Z]+":/', function($r) { return strtolower($r[0]); }, $s);print_r(json_decode($s));

stdClass Object(    [a] => 1    [b] => 2    [c] => 3    [d] => stdClass Object        (            [aa] => 11            [bb] => 22            [cc] => 33        ))

1.先json_encode把对象转字符串
2.使用preg_replace_callback 调用 strtolower把 "*": 转为小写，相当于把遍历改成正则替换。
3.json_decode 把字符串转为对象。