问题有点绕，头晕者勿进^_^

array ( 0 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'1'),
1 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>2),
2 => array ( 'id' => '11', 'title' => 'b','type' => '2', 'bian'=>'1'),
3 => array ( 'id' => '11', 'title' => 'c','type' => '2', 'bian'=>'2'),
)
当type=1去除相同id重复并且key变成ID，当type=2时KEY变成id_bian的形式,最终转成以下数组
array ( 0 => array ( '10' => '', '11_1' => '','11_2' => ''),)
然后在与下面数组合并
array ( 0 => array ( '10' => '1','11_2' => '1'),
1 => array ( '10' => '1','11_2' => '1'),
2 => array ( '11_1' => '1','11_2' => '1'),
3 => array ( '10' => '2','11_2' => '1'),
)
最终得到
array ( 0 => array ( '10' => '1','11_1'=>'','11_2' => '1'),
1 => array ( '10' => '1', '11_1 => '', 11_2' => '1'),
2 => array ( '10' => '', '11_1' => '1', '11_2' => '1'),
3 => array ( '10' => '2', '11_1' => '', '11_2' => '1'),
)

回复讨论(解决方案)

$a = array ( 0 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'1'),  1 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'2'),  2 => array ( 'id' => '11', 'title' => 'b','type' => '2', 'bian'=>'1'), 3 => array ( 'id' => '11', 'title' => 'c','type' => '2', 'bian'=>'2'),  );$b = array ( 0 => array ( '10' => '1','11_2' => '1'),  1 => array ( '10' => '1','11_2' => '1'), 2 => array ( '11_1' => '1','11_2' => '1'), 3 => array ( '10' => '2','11_2' => '1'),  );$t = array();foreach($a as $item) {  if($item['type'] == '1') {    $t[$item['id']] = '';  }else $t[$item['id'].'_'.$item['bian']] = '';}$c = array();foreach($b as $v) {  $r = array();  foreach($t as $k=>$n) $r[$k] = @$v[$k];  $c[] = $r;}print_r($c);

Array(    [0] => Array        (            [10] => 1            [11_1] =>             [11_2] => 1        )    [1] => Array        (            [10] => 1            [11_1] =>             [11_2] => 1        )    [2] => Array        (            [10] =>             [11_1] => 1            [11_2] => 1        )    [3] => Array        (            [10] => 2            [11_1] =>             [11_2] => 1        ))

$a = array ( 0 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'1'),  1 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'2'),  2 => array ( 'id' => '11', 'title' => 'b','type' => '2', 'bian'=>'1'), 3 => array ( 'id' => '11', 'title' => 'c','type' => '2', 'bian'=>'2'),  );$b = array ( 0 => array ( '10' => '1','11_2' => '1'),  1 => array ( '10' => '1','11_2' => '1'), 2 => array ( '11_1' => '1','11_2' => '1'), 3 => array ( '10' => '2','11_2' => '1'),  );$t = array();foreach($a as $item) {  if($item['type'] == '1') {    $t[$item['id']] = '';  }else $t[$item['id'].'_'.$item['bian']] = '';}$c = array();foreach($b as $v) {  $r = array();  foreach($t as $k=>$n) $r[$k] = @$v[$k];  $c[] = $r;}print_r($c);

Array(    [0] => Array        (            [10] => 1            [11_1] =>             [11_2] => 1        )    [1] => Array        (            [10] => 1            [11_1] =>             [11_2] => 1        )    [2] => Array        (            [10] =>             [11_1] => 1            [11_2] => 1        )    [3] => Array        (            [10] => 2            [11_1] =>             [11_2] => 1        ))

如果在$C里追加$t做为元素是不是要重新遍历？
追加 array ( '10' => '', '11_1' => '','11_2' => '')做为$c的

不太明白你的意思

不太明白你的意思

$a = array ( 0 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'1'),  1 => array ( 'id' => '10', 'title' => 'a','type' => '1', 'bian'=>'2'),  2 => array ( 'id' => '11', 'title' => 'b','type' => '2', 'bian'=>'1'), 3 => array ( 'id' => '11', 'title' => 'c','type' => '2', 'bian'=>'2'),  );$b = array ( 0 => array ( '10' => '1','11_2' => '1'),  1 => array ( '10' => '1','11_2' => '1'), 2 => array ( '11_1' => '1','11_2' => '1'), 3 => array ( '10' => '2','11_2' => '1'),  );$t = array();foreach($a as $item) {  if($item['type'] == '1') {    $t[$item['id']] = '';  }else $t[$item['id'].'_'.$item['bian']] = '';}$c = array();foreach($b as $v) {  $r = array();  foreach($t as $k=>$n) $r[$k] = @$v[$k];  $c[] = $r;}print_r($c);

就是数组a整里的结果插到$c中，是不是一定要把$c在遍历一次？

并没有遍历 $c 啊