sql，去重查询distinct

select DISTINCT `object_id`, t3.width as width, t3.height as height,t3.ismark as ismark, t2.rtime as add_time,t1.add_author as add_author,t1.image_url as image_url,t1.id as id,t1.browse_real_cnt as browse_real_cnt from comments as t2 left join ornamentations as t1 on t1.id = t2.object_id left join ornamentation_images as t3 on t3.ornamentation_id = t1.id where ( t2.uid = 1013 ) AND ( t1.enable = '0' ) ORDER BY t2.id desc LIMIT 0,5 

回复讨论(解决方案)

DISTINCT 作用于整行
你的3个表中只要存在一对多的情况就难说了

DISTINCT 作用于整行
你的3个表中只要存在一对多的情况就难说了

再套一个 select

select DISTINCT * from   (`object_id`, t3.width as width, t3.height as height,t3.ismark as ismark, t2.rtime as     add_time,t1.add_author as add_author,t1.image_url as image_url,t1.id as id,t1.browse_real_cnt as   browse_real_cnt   from comments as t2   left join ornamentations as t1 on t1.id = t2.object_id   left join ornamentation_images as t3 on t3.ornamentation_id = t1.id   where ( t2.uid = 1013 ) AND ( t1.enable = '0' )   ORDER BY t2.id desc) T LIMIT 0,5

再套一个 select

select DISTINCT * from   (`object_id`, t3.width as width, t3.height as height,t3.ismark as ismark, t2.rtime as     add_time,t1.add_author as add_author,t1.image_url as image_url,t1.id as id,t1.browse_real_cnt as   browse_real_cnt   from comments as t2   left join ornamentations as t1 on t1.id = t2.object_id   left join ornamentation_images as t3 on t3.ornamentation_id = t1.id   where ( t2.uid = 1013 ) AND ( t1.enable = '0' )   ORDER BY t2.id desc) T LIMIT 0,5

哦，漏了 select
..... from
( select `object_id`, t3.width as....