a表：
id name banji_id //banji_id即为b表的id
1 张龙 1
2 张龙 2
3 李四 1
3 李四 5
5 王五 3
6 赵虎 2
7 赵虎 1
8 赵虎 4
b表：
id km sj1 sj2
1 珠心算 2015 春季
2 口才 2015 春季
3 作文 2015 春季
4 数学 2015 春季
5 英语 2014 秋季
张龙是在2015春季学了珠心算和口才；
赵虎是在2015春季学了珠心算和口才和数学；
李四是在2014秋季学的英语，2015春学的珠心算；
我想做一个按纽，点击后搜索出张龙、赵虎（即在同一期学多科的学员）；
而李四虽然是不同科目，但李四由于是不同学期，所以不在显示之列
回复讨论(解决方案)
select name from (select a.*, b.km, b.sj1, b.sj2, count(*) as cou from a join b on a.banji_id = b.id group by name, sj1, sj2) as c where cou >= 2;
不知道有没有更简单的方法。。
GROUP BY xy.name,bj.shijian_1,bj.shijian_2 HAVING COUNT(*)>1
GROUP BY xy.name,bj.kemu_1 HAVING COUNT(*)<=1
怎么把这两句合在一起用？？
select a.id, name from a, b where a.banji_id=b.id group by name,sj1,sj2 having count(*) > 1
select a.id, name from a, b where a.banji_id=b.id group by name,sj1,sj2 having count(*) > 1
用这个可以了，但还有两个问题：
1、在分页时显示不正确，
function get_xueyuan_count($duoke.......省略)
{
global $fdyu,$db;
......省略
if($duoke!=0)
{
$sql_where .= " and xy.cur_banji_id=bj.banji_id group by xy.name,bj.shijian_1,bj.shijian_2 having count(*) > 1";
}
$sql = "SELECT COUNT(distinct xy.xy_id) FROM ".$fdyu->table('oa_xueyuan')." as xy left join
".$xfsql.
$fdyu->table('oa_banji') . " as bj on bj.banji_id=xy.cur_banji_id left join ".
$fdyu->table('oa_banji') . " as bj_1 on bj_1.banji_id=xy.pre_banji_id
".$xiashu.
$sql_where;
$count = $db->getOne($sql);
return $count;
}
function get_xueyuan_list($duoke.......省略)
{
global $fdyu,$db;
......省略
if($duoke!=0)
{
$sql_where .= " and xy.cur_banji_id=bj.banji_id group by xy.name,bj.shijian_1,bj.shijian_2 having count(*) > 1";
}
$sql = "SELECT COUNT(distinct xy.xy_id) FROM ".$fdyu->table('oa_xueyuan')." as xy left join
".$xfsql.
$fdyu->table('oa_banji') . " as bj on bj.banji_id=xy.cur_banji_id left join ".
$fdyu->table('oa_banji') . " as bj_1 on bj_1.banji_id=xy.pre_banji_id
".$xiashu.
$sql_where;
$res = $db->selectLimit($sql, $size, ($page-1) * $size);
$arr = array();
if ($res)
{
while ($row = $db->fetchRow($res))
{
......省略
}
}
}
2、我想把学多科的名单都显示，这句 and xy.cur_banji_id=bj.banji_id group by xy.name,bj.shijian_1,bj.shijian_2 having count(*) > 1应该怎么改
张龙
张龙
赵虎
赵虎
赵虎
