php中mysql查询用变量替换怎么弄

回复讨论(解决方案)

$names = '"张三','李四','王五'";
$sql = "select * form t where name in ($names)";

$ar = array("张三', '李四', '王五');
$names = join("'", $a);
$sql = "select * form t where name in ('$names')";

还可以
$sql = "select * form t where find_in_set(name, ''张三,'李四,'王五')";