php表单跳转保留数据

	$con = mysql_connect("localhost","root","w123456");
	if (!$con)
	  {
	  die('Could not connect: ' . mysql_error());
	  }

		mysql_select_db("peixunrecord", $con);
		mysql_query("set names 'utf8'");

	$bumen = $_POST['bumen'];
	$keduimokuai = $_POST['keduimokuai'];
	$xingming = $_POST['xingming'];
	$peixunshijian = $_POST['peixunshijian'];
	$keti = $_POST['keti'];
	$xinde = $_POST['xinde'];
	$sql="INSERT INTO record (bumen,keduimokuai,xingming,peixunshijian,keti,xinde) VALUES ('$bumen','$keduimokuai','$xingming','$peixunshijian','$keti','$xinde')";
	if (!mysql_query($sql,$con))
	  {
	  die('Error: ' . mysql_error());
	  }
     
         这块怎么能实现需求呢？谢谢了！

	 //echo "";
	 //echo "提交成功 3秒后自动跳转";
	// echo "若没自动跳转，请点击这里返回";
	 //header("Refresh:5;url=http://www.baidu.com");
	mysql_close($con);
?>