array( 'id' => '2', 'b' => 0,">
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问个PHP数组合并的有关问题~请

时间:2021-07-01 10:21:17 帮助过:13人阅读

问个PHP数组合并的问题~请高手指点
$arr1=array(
"0"=>array(
'id' => '2',
'b' => 0,
'num' => 4

),

"1"=>array(
'id' => '1',
'b' => 0,
'num' => 4
)
);
$arr2=array(
"1"=>array(
'id' => '3',
'b' => 0,
'num' => 4

),

"2"=>array(
'id' => '2',
'b' => 0,
'num' => 4
)
);

想要合并这个两个数组,判断条件,id,b两个元素都相同的情况的NUM值相加。新数组键值重新排列0 1 2 3
求高手指点。谢谢。
------解决思路----------------------
$arr1=array(
"0"=>array(
'id' => '2',
'b' => 0,
'num' => 4

),

"1"=>array(
'id' => '1',
'b' => 0,
'num' => 4
)
);
$arr2=array(
"1"=>array(
'id' => '3',
'b' => 0,
'num' => 4

),

"2"=>array(
'id' => '2',
'b' => 0,
'num' => 4
)
);
foreach($arr1 as $v) $res["$v[id]_$v[b]"] = $v;
foreach($arr2 as $v)
if(isset($res["$v[id]_$v[b]"])) $res["$v[id]_$v[b]"]['num'] += $v['num'];
else $res["$v[id]_$v[b]"] = $v;
print_r(array_values($res));
Array
(
[0] => Array
(
[id] => 2
[b] => 0
[num] => 8
)

[1] => Array
(
[id] => 1
[b] => 0
[num] => 4
)

[2] => Array
(
[id] => 3
[b] => 0
[num] => 4
)

)

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