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PHP怎么计算两个日期相差几个月

时间:2021-07-01 10:21:17 帮助过:19人阅读

PHP怎样计算两个日期相差几个月?

function getMonthNum( $date1, $date2, $tags='-' ){
$date1 = explode($tags,$date1);
$date2 = explode($tags,$date2);
return abs($date1[0] - $date2[0]) * 12 + abs($date1[1] - $date2[1]);
}

echo getMonthNum("2013-02-01","2014-01-01",'-');

?>


以上代码计算出相差13个月,不知道该怎么改才能正常一些?
------解决思路----------------------
去掉 abs
返回 -11 表示 2013-02-01 比 2014-01-01 少 11 个月
当然你也可以将整个返回值 abs,但这样就只是知道差 11 个月,但不知道是多了还是少了
------解决思路----------------------


function getMonthNum($date1,$date2){
$date1_stamp=strtotime($date1);
$date2_stamp=strtotime($date2);
list($date_1['y'],$date_1['m'])=explode("-",date('Y-m',$date1_stamp));
list($date_2['y'],$date_2['m'])=explode("-",date('Y-m',$date2_stamp));
return abs($date_1['y']-$date_2['y'])*12 +$date_2['m']-$date_1['m'];
}

echo getMonthNum("2013-02-01","2014-01-01");

echo getMonthNum("20130201","20140101");

echo getMonthNum("201302","201401");


------解决思路----------------------

function getMonthNum( $date1, $date2, $tags='-' ){
$date1 = explode($tags,$date1);
$date2 = explode($tags,$date2);
if ($date1[0]>=$date2[0]){
return abs($date1[0] - $date2[0]) * 12 + abs($date1[1] - $date2[1]);
}
else{
return abs($date2[0] - $date1[0]) * 12 - abs($date1[1] - $date2[1]);
}
}

echo getMonthNum("2013-02-01","2014-01-01",'-');

?>


------解决思路----------------------
上面写错了。。。。。重发:



function getMonthNum($date1,$date2){
$date1_stamp=strtotime($date1);
$date2_stamp=strtotime($date2);
list($date_1['y'],$date_1['m'])=explode("-",date('Y-m',$date1_stamp));
list($date_2['y'],$date_2['m'])=explode("-",date('Y-m',$date2_stamp));
return abs(($date_2['y']-$date_1['y'])*12 +$date_2['m']-$date_1['m']);
}

echo getMonthNum("2013-02-01","2014-01-01");

echo getMonthNum("20130201","20140101");

echo getMonthNum("201302","201401");

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