php【数组对比输出】解决办法

php【数组对比输出】

$array1=array("1","2","3","4","5","6");//此数据值固定。
$array2=array("1","3","6","4");//此数据值不固定。

实现效果：
array2与array1对比后array2没有的值用0代替。
结果：
1,0,3,4,0,6

请问怎么实现
------解决思路----------------------

$arr = array();
$x;
foreach($array2 as $k => $v) {
    x = array_search($v,$array1);
     if (x) {
        $arr[$k] = $v;
    } else {
        $arr[$k] = 0;
    }
}

------解决思路----------------------

$array1=array("1","2","3","4","5","6");//此数据值固定。
$array2=array("1","3","6","4");//此数据值不固定。
$arr = array();
foreach($array1 as $v){
	$arr[] = in_array($v, $array2) ? $v : 0;
}
print_r($arr);

------解决思路----------------------

引用

#1
$arr = array();
$x;
foreach($array2 as $k => $v) {
x = array_search($v,$array1);
if (x) {
$arr[$k] = $v;
} else {
$arr[$k] = 0;
}
}

array_search()返回的是匹配到的键名，当第一个匹配到，键名是0，if判断就不存在了，这里存在一点问题
------解决思路----------------------
php里面有个数组比较函数 array_diff的呀。
------解决思路----------------------
不错，可以借助 array_diff

$a = array("1","2","3","4","5","6");
$b = array("1","3","6","4");
$c = $a;
foreach(array_diff($a, $b) as $k=>$v) $c[$k] = 0;

print_r($c);

Array
(
    [0] => 1
    [1] => 0
    [2] => 3
    [3] => 4
    [4] => 0
    [5] => 6
)

------解决思路----------------------

$array1=array("1","2","3","4","5","6");//此数据值固定。
$array2=array("1","3","6","4");//此数据值不固定。

$c = array_diff($array1, $array2);

foreach($c as $k=>$v){
    $array1[$k] = 0;
}

print_r($array1);

Array
(
[0] => 1
[1] => 0
[2] => 3
[3] => 4
[4] => 0
[5] => 6
)