初学者问下PHP取出MYSQL数据，然后倒置顺序

菜鸟 问下PHP取出MYSQL数据，然后倒置顺序
mysql数据


php代码：

$res_ip = mysql_query("select * from ip  order by id DESC limit 0,5");
while($row_ip = mysql_fetch_array($res_ip)){
    $ip_ip[] = intval($row_ip['ip']);
	$time_ip[] = date($row_ip['time']);
}
$data_ip = array(array("name"=>"IP流量","data"=>$ip_ip));
$data_ip = json_encode($data_ip);
$times_ip = json_encode($time_ip);
$times_ip = str_replace('2015-', '', $times_ip);

结果：

["01-25","01-25","01-24","01-23","01-22"]

[{"name":"IP\u6d41\u91cf","data":[12632220,12735020,127350,2213488,2348888]}]

想要的效果：

["01-22","01-23","01-24","01-25","01-26"]

[{"name":"IP\u6d41\u91cf","data":[2348888,2213488,127350,12735020,12632220]}]

说明： 就是相当于 把取出的最新5条数据，倒置过来。正常的取出来的5条最新数据是：5 4 3 2 1. 想要的是 1 2 3 4 5。 5 是最新的数据。

致谢！
------解决思路----------------------
id desc 改成 id asc 是不行的！
id desc 的本意是取最新数据，而 id asc 是取最旧的数据
要用 array_reverse 转置数组

$data_ip = array(array("name"=>"IP流量","data"=> array_reverse($ip_ip)));
$data_ip = json_encode($data_ip);
$times_ip = json_encode(array_reverse($time_ip));
$times_ip = str_replace('2015-', '', $times_ip);