版主sqlsrv自个儿弄的简单类还需要您的帮助

版主 sqlsrv 自己弄的简单类还需要您的帮助

class DB_sqlsrv
{
    var $query;
	var $result;
	function DB_sqlsrv($text)
	{
		
				$serverName = "192.168.0.1";
				$connectionInfo = array(
				"UID"=>"sa",
				"PWD"=>"sa",
				"Database"=>"ttt"
				$conn = sqlsrv_connect( $serverName, $connectionInfo);
				$this->query=sqlsrv_query($conn, $text);
	}
	//以对象形式取得查询结果数据
	function Record()
	{
		$this->result=sqlsrv_fetch_object($this->query);
		return ($this->result)?($this->result):false;
	}
}
$sql=new DB_sqlsrv("select * from username");
$record=$sql->Record();

出错 PHP Warning: sqlsrv_fetch_object(): 2 is not a valid ss_sqlsrv_stmt resource in E:\web\test\test\test.php on line 20
$this->result=sqlsrv_fetch_object($this->query);
这句有问题，我看看类好像没有问题的。请教谢谢。
------解决思路----------------------
$this->query=sqlsrv_query($conn, $text);
执行失败

你 var_dump($this->query); 看看是什么