=-求大神指导下非常感谢~解决办法

= - 求大神 指导下 非常感谢 ~

<br><!--?php<br /--><br>echo "姓名：".$_POST['name']."<br>";<br>// echo $_POST['price']."<br>";
<br>// echo $_POST['type']."<br>";
<br>// echo $_POST['name']."<br>";
<br>echo "电话：". $_POST['tel']."<br>";<br>echo "电邮：".$_POST['email']."<br>";
<br>echo "QQ：".$_POST['QQ']."<br>";<br>echo "地址：".$_POST['addr']."<br>";<br>echo "性别：".$_POST['sex']."<br>";<br>echo "商品名称：".$_POST['brandname']."<br>";<br>echo "商品品牌：".$_POST['commoditybrand']."<br>";<br>echo "商品编号:".$_POST['productID']."<br>"; 
<br>echo "商品序号:".$_POST['ordername']."<br>";<br>echo "商铺名称：".$_POST['shopname']."<br>";<br>echo "商铺地址:".$_POST['shopaddr']."<br>";<br>echo "发票编号:".$_POST['invoicenumber']."<br>";<br>echo "购买日期:".$_POST['purchasingdate']."<br>";<br><br><br>$dingdanhao = date("Y-m-dH-i-s");<br>$dingdanhao = str_replace("-","",$dingdanhao);<br>$dingdanhao .= rand(1000,2000);<br><br>echo "保用编号:".  $dingdanhao;<br><br> <br>$name=$_POST['name'];<br>$tel=$_POST['tel'];<br>$email=$_POST['email'];<br>$QQ=$_POST['QQ'];<br>$sex=$_POST['sex'];<br>$brandname=$_POST['brandname'];<br>$commoditybrand=$_POST['commoditybrand'];<br>$productID=$_POST['productID']; <br>$ordername=$_POST['ordername'];<br>$shopname=$_POST['shopname'];<br>$shopaddr=$_POST['shopaddr'];<br>$invoicenumber=$_POST['invoicenumber'];<br>$purchasingdate=$_POST['purchasingdate'];<br><br><br>require_once("conn.php");<br>if(mysql_query("insert into name set <br><br>name='$name',tel='$tel',email='$email',QQ='$QQ',sex='$sex',brandname='$brandname',commodity<br><br>brand='$commoditybrand',productID='$productID',ordername='$ordername',shopname='$shopname',<br><br>shopaddr='$shopaddr',invoicenumber='$invoicenumber',purchasingdate='$purchasingdate'",<br><br>$conn)){<br>echo "添加成功！查看数据库";<br>}<br> else{<br>
echo '添加失败！';<br>}<br><br>mysql_close($con);<br>?><br>

错误报告 如下 ：
Notice: Undefined variable: con in D:\wamp\www\WWW\post.php on line 55
Call Stack


( ! ) Warning: mysql_close() expects parameter 1 to be resource, null given in D:\wamp\www\WWW\post.php on line 55

= - 求助
------解决思路----------------------
mysql_close($con);改成mysql_close($conn);
------解决思路----------------------
$con 写错了，应该是$conn

你上面的程序有写的。
mysql_query("insert into name set

name='$name',tel='$tel',email='$email',QQ='$QQ',sex='$sex',brandname='$brandname',commodity

brand='$commoditybrand',productID='$productID',ordername='$ordername',shopname='$shopname',

shopaddr='$shopaddr',invoicenumber='$invoicenumber',purchasingdate='$purchasingdate'",

$conn))